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9966 [12]
3 years ago
9

Fun facts about acetic acid. (Doesn’t have to be chemistry related!)

Chemistry
1 answer:
ipn [44]3 years ago
3 0

Answer:

Acetic acid is often called “glacial acetic acid”. The origin of this name can be attributed to acetic acid's high freezing point. Acetic acid freezes into a solid at a temperature very close to room temperature: 16.5 ºC, or 62 ºF. When it freezes, it kind of looks like ice; because of the word “glacial”.

Explanation:

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Suppose 0.09886 M KOH is titrated into 15.00 mL H2SO4 of unknown concentration until the equivalence point is reached. It takes
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2 Mol base : 1 Mol acid

Explanation:

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Is burning physical or chemical change?
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Explanation:

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What mass of oxygen would form from 2.0 moles of water ​
kicyunya [14]

The reaction of the decomposition of water into oxygen gas and hydrogen is balanced as such:

2H_{2} O  ->  2H_{2} + O_{2}

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1 mol O2 is equivalent to 32g O2 (1 mol O2 * \frac{32 g O2}{1molO2} )

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7 0
4 years ago
How much heat energy is required to raise the temperature of 0.367 kg of copper from 23.0 C to 60.0 C ? The specific heat of cop
mojhsa [17]
Note: We must keep the units we use consistent. The Cp is given in cal/gC so we will use cal for energy, grams for mass and C for temperature.
1)
Heat supplied can be calculated using:
Q = mCpΔT; where m is the mass, Cp is the specific heat capacity and ΔT is the temperature change.
Q = 367 x 0.092 x (60 - 23)
Q = 125 Cal

2)
Using the same equation:
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5 0
3 years ago
Nitrogen gas at 300 k and 200 kpa is throttled adiabatically to a pressure of 100 kpa if the change in kinetic energy is negligb
erastovalidia [21]

Answer:

The temperature of the Nitrogen after throttling is  T_2 = 300 \  K

Explanation:

From the question we are told that

   The  temperature is  T_1 =  300 \  K

    The pressure is  P =  200 \  kPa  =  200 * 10^{3} \  Pa

    The pressure after being  P_1 =  100 \  kPa =  100 * 10^{3} \  Pa

   

Generally from the first law of thermodynamics we have that

      Q - W =  \Delta U + \Delta  K

Here \Delta U  is the change internal  energy which is mathematically represented as

            \Delta U =  C_p  (T_2 - T_1)

Here      C_p is the specific heat of the gas at constant pressure

        \Delta K  is the change kinetic energy which is negligible

         Q  is the thermal  energy  which is Zero for an adiabatic process

         W  is the work done and the value is zero given that the gas was throttled adiabatically

So

      0=  \Delta U +0

=>   \Delta U  = 0

=>  (T_2 - 300)  = 0

=>   T_2 = 300 \  K

     

3 0
3 years ago
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