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lys-0071 [83]
3 years ago
6

Nitrogen gas at 300 k and 200 kpa is throttled adiabatically to a pressure of 100 kpa if the change in kinetic energy is negligb

le the temperature of the nitrogen after throttling will be:_________
Chemistry
1 answer:
erastovalidia [21]3 years ago
3 0

Answer:

The temperature of the Nitrogen after throttling is  T_2 = 300 \  K

Explanation:

From the question we are told that

   The  temperature is  T_1 =  300 \  K

    The pressure is  P =  200 \  kPa  =  200 * 10^{3} \  Pa

    The pressure after being  P_1 =  100 \  kPa =  100 * 10^{3} \  Pa

   

Generally from the first law of thermodynamics we have that

      Q - W =  \Delta U + \Delta  K

Here \Delta U  is the change internal  energy which is mathematically represented as

            \Delta U =  C_p  (T_2 - T_1)

Here      C_p is the specific heat of the gas at constant pressure

        \Delta K  is the change kinetic energy which is negligible

         Q  is the thermal  energy  which is Zero for an adiabatic process

         W  is the work done and the value is zero given that the gas was throttled adiabatically

So

      0=  \Delta U +0

=>   \Delta U  = 0

=>  (T_2 - 300)  = 0

=>   T_2 = 300 \  K

     

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