Question

1. The position of a particle moving along a coordinate axis is given by: s(t) = t^2 - 5t + 1. Find the speed of the particle

Answer 1

Answer:

$v(t) = 2t - 5$

Step-by-step explanation:

Given

$s(t) = t^2 - 5t + 1$

Required

The speed of the particle

To do this, we simply differentiate the position function

i.e.

$v(t) = s'(t)$

So, we have:

$s(t) = t^2 - 5t + 1$

Differentiate

$s'(t) = 2t - 5 + 0$

$s'(t) = 2t - 5$

So, the speed function is:

$v(t) = 2t - 5$