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REY [17]
3 years ago
10

the population of a town increases at a rate proportional to its population with an initial population of 1000. The corect initi

al value problem for the population p(t) as a function of time is
Mathematics
1 answer:
anyanavicka [17]3 years ago
5 0

Answer:

This means that the correct initial value problem for the population p(t) as a function of time is is P(0) = 1000

Step-by-step explanation:

The population of a town increases at a rate proportional to its population:

This means that this situation is modeled by the following differential equation:

\frac{dP}{dt} = kP

In which k is the growth rate.

By separation of variables, the solution is given by:

P(t) = P(0)e^{kt}

In which P(0) is the initial population.

Initial population of 1000.

This means that the correct initial value problem for the population p(t) as a function of time is is P(0) = 1000

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Determine whether the ordered pair (1, 1) is a solution of the inequality. y ≤ -3x+1
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Answer:  \textsf{(1, 1) is NOT a solution of the inequality}

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Given:  y \le-3x + 1

Find:  \textsf{Determine if (1, 1) is a solution of the inequality}

Solution:  In order to determine if (1, 1) is a solution we need to plug in 1 for the x values and 1 for the y values and see if the equation evaluated to true.

<u>Plug in the values</u>

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Step-by-step explanation:

The true statements are:

Over the interval [2, 4], the local minimum is –8.

Over the interval [3, 5], the local minimum is –8.

Over the interval [1, 4], the local maximum is 0.  

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Over the interval [2, 4], the local minimum is –8.

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Over the interval [3, 5], the local minimum is –8.

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Over the interval [1, 4], the local maximum is 0.

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Over the interval [3, 5], the local maximum is 0.

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