I hope this helps you
2.(7R-15+2R-3/2+7R)-4
2. (16R-33/2)-4
2.16R-2.33/2-4
32R-33-4
32R-37
Answer:
The points which satisfy the given lines is ( 1 , 1 )
Step-by-step explanation:
Given as :
The equation of lines is
y = 3 x - 2 ........ 1 And
y = - 2 x + 3 ........ 2
From equation given
3 x - 2 = - 2 x + 3
Or , 3 x + 2 x = 3 +2
Or, 5 x = 5
So , x = 
= 1
Put the value of x in eq 1
So, y = 3 ( 1 ) - 2
Or, y = 3 - 2 = 1
∴, the points ( x , y ) = ( 1 , 1 )
Hence The points which satisfy the given lines is ( 1 , 1 ) Answer
Answer:
$192
Step-by-step explanation:
2400/48=50
50x3.84=192
Means the number you can use
remember we can't divide by zero
domain is x^2-9
set to zero to find values we can't use
x^2-9=0
x^2=9
x=+/-3
domain=all real numbers except -3 and 3
Answer:
95% confidence interval for the difference between the average mass of eggs in small and large nest is between a lower limit of 0.81 and an upper limit of 2.39.
Step-by-step explanation:
Confidence interval is given by mean +/- margin of error (E)
Eggs from small nest
Sample size (n1) = 60
Mean = 37.2
Sample variance = 24.7
Eggs from large nest
Sample size (n2) = 159
Mean = 35.6
Sample variance = 39
Pooled variance = [(60-1)24.7 + (159-1)39] ÷ (60+159-2) = 7619.3 ÷ 217 = 35.11
Standard deviation = sqrt(pooled variance) = sqrt(35.11) = 5.93
Difference in mean = 37.2 - 35.6 = 1.6
Degree of freedom = n1+n2 - 2 = 60+159-2 = 217
Confidence level = 95%
Critical value (t) corresponding to 217 degrees of freedom and 95% confidence level is 1.97132
E = t×sd/√(n1+n2) = 1.97132×5.93/√219 = 0.79
Lower limit = mean - E = 1.6 - 0.79 = 0.81
Upper limit = mean + E = 1.6 + 0.79 = 2.39
95% confidence interval for the difference in average mass is (0.81, 2.39)
