Answer:
there should be a pic or a diagram
Step-by-step explanation:
Yes. It is equivalent to 3. Combine like terms
L1: 2x+4y-3=0 ..........(1)
P: (2,0)
The point on the line L1 closest to the given point P is at the intersection of L1 with L2, which is the perpendicular passing through P.
Slope of L1=-2/4=-1/2
Slope of L2=-1/(-1/2)=2
Since it passes throug P(2,0), we can use the point-slope formula:
(y-0)=2(x-2) =>
L2: 2x-y-4=0.............(2)
Solve for x & y using (1) and (2) to get intersection point required:
(1)-(2)
2x-2x + 4y-(-y) -3 -(-4) =0
5y=-1, y=-1/5
Substitute y=1/5 in equation (1)
2x+4(-1/5)-3=0 =>
2x-19/5=0
x=19/10
=> the point on L1 closest to (2,0) is (19/10, -1/5)
Answer:
Remaining tickets left to distribute, A = (300 - 10m)
Step-by-step explanation:
a) Let the number of choir members be m
Let the number of tickets remaining after the distribution be A
Each choir member is to get 10 tickets each.
Number of tickets to be given to the members = 10m
original number of tickets = 300
So, number of tickets remaining after distribution, A = 300 - 10m (provided that m ≤ 30)
b) The independent variable in this expression is m (the number of choir members)
And the dependent variable is A (the number of tickets left after the distribution which depends on the number of choir members, m)
Hope this Helps!!!
I suck at explaining but I know it’s 4
