DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.
<h3>
Congruent shape</h3>
Two shapes are said to be congruent if they have the same shape, all their corresponding angles and sides are congruent to one another.
Given that DE = AB and BC = EF.
In right triangle DEF, using Pythagoras:
DF² = DE² + EF²
Also, In right triangle ABC, using Pythagoras:
AC² = AB² + BC²
But DE = AB and EF = BC, hence:
AC² = DE² + EF²
AC² = DF²
Taking square root of both sides, hence:
AC = DF
Since DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.
Find out more on Congruent shape at: brainly.com/question/11329400
3 is the answer when u subtract 15- 13
Answer:
SU=25
Step-by-step explanation:
We can set up a ratio as STU and SQR are similar because of the SAS similarity theorem.
TQ:SQ
SQ=ST+TQ=10+6=16
6:16=3:8
Therefore the ratio of STU:SQR is 3:8
We can use this to find SU
UR:SR=3:8
15:SR=3:8
Cross multiply
3SR=120
SR=40
SU=SR-UR
SU=40-15
SU=25
Answer:
3.60 was the tip; 27.60 was what Sam paid total
Step-by-step explanation:
24 x 0.15 = 3.6
