68 degrees because they’re vertical angles
Answer:
Draw a perpendicular line from point A to line segment BC. Name the intersection of said line at BC “E.” You now have a right angled triangle AED.
Now, you know AD = 6 m. Next, given that the trapezoid is a normal one, you know that the midpoints of AB and DC coincide. Therefore, you can find the length of DE like so, DE = (20–14)/2 = 3 m.
Next, we will use the cosign trigonometric function. We know, cos() = adjacent / hypotenuse. Hence, cosx = 3/6 = 1/2. Looking it up on a trigonometric table we know, cos(60 degrees) = 1/2. Therefore, x = 60 degrees.
Alternatively, you could simply use the Theorem for normal trapezoids that states that the base angles will be 60 degrees. Hope this helps!
Answer:
1) x=4-y-z
2) x=-12+4y-4z/3
3) x=-1+y+4z/2
Step-by-step explanation:
1) Subtract y+z from both sides.
x+y+z-(y+z)=4-(y+z)
Simplify
x=4-y-z
2) Subtract -4y+4z from both sides.
-4y+4z-(-4y+4z)=12-(-4y+4z)
Simplify
-3x=12+4y-4z
Divide both sides by -3
-3x/-3=12/-3+4y/-3-4z/-3
x=-12+4y-4z/3
3) Subtract -y-4z from both sides.
2x-y-4z-(-y-4z)=-1-(-y-4z)
Simplify
2x=-1+y+4z
Divide both sides by 2
2x/2=-1/2+y/2+4z/2
Simplify
x=-1+y+4z/2
Hope this helps! Pls give brainliest!
Answer:
$17.10
Step-by-step explanation:
19% of 90 is 17.1
9514 1404 393
Answer:
-2x +4
Step-by-step explanation:
We can write the polynomial p(x) in terms of the factors (x+2) and (x-3) as ...
p(x) = (x+2)(x-3)q(x) +ax +b
Where ax+b is the remainder from division by x^2 -x -6 = (x+2)(x-3). The values of 'a' and 'b' can be found from ...
p(-2) = 8 = -2a +b
p(3) = -2 = 3a +b
Subtracting the first equation from the second gives ...
(3a +b) -(-2a +b) = (-2) -(8)
5a = -10
a = -2
Then the first equation tells us ...
8 = -2(-2) +b
4 = b
So, the remainder from division by (x^2 -x -6) is (-2x +4).