Our basis for this equality is the pythagorean theorems of trigonometry. There are three equations for the pythagorean theorems. These are:
sin²x + cos²x =1
1 + tan²x = sec² x
1 + cot² x = csc² x
These are all derived from circle geometry on the cartesian plane. Now, the useful trigonometric property to be used is the third one. Rearranging this, we come up with
cot²x - csc²x = -1
This coincided with the given equation. Therefore, this is true. This is because it is already established from the pythagorean theorems.
Answer: 3.25%
Step-by-step explanation:
Answer:
The answer to your question is the letter a
Step-by-step explanation:
| 1 4 -1 | | 2 -1 |
| 3 2 2 | | 0 3 | Product = 2 x 3 and 3 x 2 = 2 x 2
| 5 2 | It is possible to do this product,
the result will be a 2 x 2 matrix
Process
1.- Multiply first row by first column and second row by second column.
2.- Multiply the second row by the first column and second row by the second column.
= (1 x 2) + (4 x 0) + (-1 x 5) = 2 + 0 - 5 = -3
= (1 x -1) + (4 x 3) + (-1 x 2) = -1 + 12 - 2 = 9
= (3 x 2) + (2 x 0) + (2 x 5) = 6 + 0 + 10 = 16
= (3 x -1) + (2 x 3) + (2 x 2) = -3 + 6 + 4 = 7
Result
| 3 9 |
| 16 7 |
Answer:
Assignment: 01.07 Laboratory TechniquesAssignment: 01.07 Laboratory TechniquesAssignment: 01.07 Laboratory Techniques
Step-by-step explanation:
Assignment: 01.07 Laboratory Techniques
Assignment: 01.07 Laboratory TechniquesAssignment: 01.07 Laboratory Techniques
Answer:
4, 7, 10, 13, 16, 19, 22
Step-by-step explanation:
Not sure if there is more to this question but here is what I assume:
We want to find the first 7 terms of this equation given 3n+4
Assuming we are starting at 0 we plug 0 in for n.
3(0) + 4 → 4
So our first answer is 4
We continue by pugging in the next numbers after that to get to the first 7 terms
3(1) + 4 → 7
3(2) + 4 → 10
3(3) + 4 → 13
3(4) + 4 → 16
3(5) + 4 → 19
3(6) + 4 → 22
