2 years ago

Find the missing lengths in the given triangle

Mathematics

1 answer:

katovenus [111]2 years ago

3 0

90° becuase 60+30 = 90 and 90+90=180

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A bus and a car leave the same place and traveled in opposite directions. If the bus is traveling at 50 mph and the car is trave

harina [27]

Answer:

After Two Hours.

Step-by-step explanation:

A simple way to do it is to:

1. Add 50+55, it is equal to 105. This is after one hour, so we know that it's more than this.

2. Add 50+55 to 105, This is after two hours, and we get 210, so we know that it has to be equal to 2 hours.

6 0

2 years ago

HELP ASAP!!!! Please!!! Is my answer correct?!?! :) will give brainliest if correct!

MrMuchimi

Vertical stretch of 4 and shift of 4 to the right is: g(x) = 4*f(x-4)

So: g(x) = -12(x-4)

You are correct.

6 0

3 years ago

A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n = 1083 and x=550 who said

Zigmanuir [339]

Step-by-step explanation:

p = x / n

p = 550 / 1083

p = 0.5078

5 0

3 years ago

Find z 1 ÷ z 2 for z 1 = 9(cos225° + isin225°) and z 2 = 3(cos45° + isin45°).

olga nikolaevna [1]

$\bf \qquad \textit{division of two complex numbers} \\\\ \cfrac{r_1[cos(\alpha)+isin(\alpha)]}{r_2[cos(\beta)+isin(\beta)]}\implies \cfrac{r_1}{r_2}[cos(\alpha - \beta)+isin(\alpha - \beta)] \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \begin{cases} z1=9[cos(225^o)+i~sin(225^o)]\\\\ z2=3[cos(45^o)+i~sin(45^o)] \end{cases}\implies \cfrac{z1}{z2}\implies \cfrac{9[cos(225^o)+i~sin(225^o)]}{3[cos(45^o)+i~sin(45^o)]} \\\\\\ \cfrac{9}{3}[cos(225^o-45^o)+isin(225^o-45^o)]\implies 3[cos(180^o)+i~sin(180^o)] \\\\\\ 3[(-1)+i~(0)]\implies -3+0i$