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2 years ago

For the acute angles in a right triangle,

Mathematics

1 answer:

Romashka [77]2 years ago

5 0

Answer:

answer for this solution is 10 degrees

Step-by-step explanation:

sin x + cos x = 90

5x + 3x +10 = 90

x = 10

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What is the value of the expression?<br> 5(6-10)

MArishka [77]

Answer:

-20

Step-by-step explanation:

multiply 5 and 6 then 5 and -10

30-50=-20

6 0

3 years ago

Y=-x+3 y = -2.x +7 = 5.

lyudmila [28]

Answer:

Slope: 3/5

y-intercept: 7

Step-by-step explanation:

5 0

3 years ago

Using the Addition Method, find the value of x in the

allochka39001 [22]

Step-by-step explanation:

3x+2y=2------------1

-3x+5y=5-----------2

adding 1 and 2 we get

7y=7

y=1

and from (1),we get

3x+2×1=2

3x=0

x=0 is the required value of x.

8 0

2 years ago

The art teacher needs 70 markers for her classes. The markers come in packages of 15. How many packages of markers will the art

Temka [501]

Answer:

Step-by-step explanation:

Take the number of markers and divide by the number in each package

70/15

4.6666repeating

Round to the nearest whole number to determine the number of packages

They will need to buy 5 packages

5 0

3 years ago

The density of a American white oak tree is 752 kilograms per cubic meter. If the trunk of an American white oak tree has a circ

LuckyWell [14K]

Check the picture below.

$\bf \textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r=radius\\ \cline{1-1} C=4.5 \end{cases}\implies 4.5=2\pi r\implies \cfrac{4.5}{2\pi }=r \\\\[-0.35em] ~\dotfill$

$\bf \textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} r=radius\\ h=height\\ \cline{1-1} h=8\\ r=\frac{4.5}{2\pi } \end{cases}\implies V=\pi \left( \cfrac{4.5}{2\pi } \right)^2(8)\implies V=\begin{matrix} \pi \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix} \cdot \cfrac{20.25}{\begin{matrix} 4 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}\underset{\pi }{\begin{matrix} \pi^2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix} }}(\stackrel{2}{\begin{matrix} 8 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}})$

$\bf V=\cfrac{40.5}{\pi }~cm^3~\hspace{9em} \stackrel{\textit{since density is }752kg~per~cm^3}{density\implies 752\left( \cfrac{40.5}{\pi } \right)}\qquad \approx ~~9694$

8 0

3 years ago