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gladu [14]
3 years ago
14

Find the value of x in kite EFGH​

Mathematics
2 answers:
blsea [12.9K]3 years ago
8 0
Answer:

X = 105

Explanation:
kolbaska11 [484]3 years ago
3 0

Answer:

x = 105

Step-by-step explanation:

the sum of all interior angles of any four-sided figure has 360 degrees

∡F and ∡H are equal

add all four expressions and set them equal to 360

x + (x + 5) +( x + 5) + (140 - x) = 360

combine like terms

2x + 150 = 360

2x = 210

x = 105

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Factor Completely: 100x2 - 1
fredd [130]

Answer:

d

Step-by-step explanation:

100x² - 1 ← is a difference of squares and factors in general as

a² - b² = (a - b)(a + b), thus

100x² - 1

= (10x)² - 1²

= (10x - 1)(10x + 1) → d

3 0
3 years ago
What os the correct question and why​
mr_godi [17]

Answer:

maybe the second equation i.e(10+1.2)x=24

8 0
2 years ago
At a 20th high school reunion, all the classmates were asked the number of children they had. The probability of having a partic
finlep [7]

Answer:

a) We need to check two conditions:

1) \sum_{i=1}^n P_i = 1

0.05+0.14+0.34+0.24+0.11+0.07+0.02+0.02+0.01= 1

2) P_i \geq 0 , \forall i=1,2,...,n

So we satisfy the two conditions so then we have a probability distribution

b) P(C \geq 1)

And we can use the complement rule and we got:

P(C \geq 1)= 1-P(C

c) P(C=0) = 0.05

d) For this case we see that the result from part b use the probability calculated from part c using the complement rule.

Step-by-step explanation:

For this case we have the following probability distribution given:

C    0        1        2         3       4       5        6       7        8      

P  0.05   0.14   0.34   0.24  0.11  0.07  0.02  0.02  0.01

And we assume the following questions:

a) Verify that this is a probability distribution

We need to check two conditions:

1) \sum_{i=1}^n P_i = 1

0.05+0.14+0.34+0.24+0.11+0.07+0.02+0.02+0.01= 1

2) P_i \geq 0 , \forall i=1,2,...,n

So we satisfy the two conditions so then we have a probability distribution

b) What is the probability one randonmly chosen classmate has at least one child

For this case we want this probability:

P(C \geq 1)

And we can use the complement rule and we got:

P(C \geq 1)= 1-P(C

c) What is the probability one randonmly chosen classmate has no children

For this case we want this probability:

P(C=0) = 0.05

d) Look at the answers for parts b and c and explain their relationship

For this case we see that the result from part b use the probability calculated from part c using the complement rule.

5 0
3 years ago
Find the ratio in simplest form.<br><br> 30:6<br><br> A. 1:5<br> B. 4:1<br> C. 5:1
nekit [7.7K]
ANSWER

The simplest form of the ratio
30:6
is

5:1


EXPLANATION

The ratio given to us is
30:6


We can divide each term in ratio by the same number.


To find the ratio in the simplest form we divide the terms in the ratio by their highest common factor, which is
6.


This implies that,

30:6 =  \frac{30}{6} : \frac{6}{6}


We simplify this to obtain,



30:6 = 5: 1


The correct answer is C.



Alternatively,


30:6 =   \frac{30}{6}


30:6 =   \frac{5}{1}


This implies that,


30:6 =   5:1



6 0
3 years ago
Read 2 more answers
The number of lightning strikes in a year at the top of a particular mountain has a poisson distribution with a mean of 3.8. fin
atroni [7]

Let X be the number of lightning strikes in a year at the top of particular mountain.

X follows Poisson distribution with mean μ = 3.8

We have to find here the probability that in randomly selected year the number of lightning strikes is 0

The Poisson probability is given by,

P(X=k) = \frac{e^{-mean} mean^{x}}{x!}

Here we have X=0, mean =3.8

Hence probability that X=0 is given by

P(X=0) = \frac{e^{-3.8} 3.8^{0}}{0!}

P(X=0) = \frac{0.02237 * 1}{1}

P(X=0) = 0.0224

The probability that in a randomly selected year, the number of lightning strikes is 0 is 0.0224

5 0
3 years ago
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