In the first octant, the given plane forms a triangle with vertices corresponding to the plane's intercepts along each axis.



Now that we know the vertices of the surface

, we can parameterize it by

where

and

. The surface element is

With respect to our parameterization, we have

, so the surface integral is
Answer:
(-∞, -12), (2, ∞)
or
(-∞, -12) U (2, ∞)
Step-by-step explanation:
|3x + 15| > 21, |3x + 15| < -21
3x + 15 > 21, 3x + 15 < - 21
-15 -15 -15 -15
------------------ -------------------
3x > 6 3x < - 36
÷3 ÷3 ÷3 ÷3
------------ ------------------
x > 2 x < -12
(-∞, -12), (2, ∞)
or
(-∞, -12) U (2, ∞)
I hope this helps!
Answer:
Step-by-step explanation:
First, start off by solving for the slope using this formula:

Then, plug in the values: 
Solve the equation: 
That's your slope.
Then plug in one of the coordinates given in the problem for x and y and solve this equation:
y=
x+b
Hope that helped!!! :)