Answer:
Place two of them as reactants.
Explanation:
- We have the two steps of reactions:
1) N₂(g ) + O₂(g) → 2NO(g).
2) 2NO(g )+ O₂(g) → 2NO₂(g).
- Adding the two equation with cancelling the intermediate (NO), we get:
<em>N₂(g ) + 2O₂(g) → 2NO₂(g).</em>
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NO is cancelled out because there is one in each equation in the products side in eq. 1 and in oriduct side in eq. 2.
<em>So, we place two of oxygen as reactants.</em>
To solve this question, we will use Graham's law which states that:
(R1 / R2) ^ 2 = M2 / M1 where
R1 and R2 are the rates of effusion and M1 and M2 are the molar masses of the two gases.
From the periodic table, we can calculate the molar mass of O2 as follows:
molar mass of O2 = 2*16 = 32 grams
Therefore we have:
R1 / R2 = Ry / RO2 = 1/2
M1 is My we want to get
M2 is molar mass of O2 = 32 grams
Substitute in the above equation to get the molar mass of y as follows:
(1/2) ^2 = (32/My)
1/4 = 32/My
My = 32*4 = 128
Therefore, molar mass of gas y = 128 grams
10 miles per hour because 500 divided by 50 is 10
Answer:
D
Explanation:
The SI unit for density is the kilogram per cubic meter (kg/m3 ).
