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kaheart [24]
3 years ago
14

The same chemistry student has a weight of 155lbs what is the student weight in grams

Chemistry
2 answers:
Alexxx [7]3 years ago
8 0

Answer:

70306.8 grams

Explanation:

Brrunno [24]3 years ago
6 0

the answer is 70306.8 grams

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Look at the following chemical compounds. State how many molecules of each reactant are present. (I’m sorry I’ve been working on
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▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

<h3>Compound ~ \mathrm{NaOH}</h3>

Na = 1

O = 1

H = 1

<h3>Compound ~ \mathrm{CO_2}</h3>

C = 1

O = 2

<h3>Compound ~ \mathrm{3  \: CaO}</h3>

Ca = 3

O = 3

<h3>Compound ~ \mathrm{2 MgCl_2}</h3>

Mg = 2

Cl = 4

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3 years ago
Purple Group Header Warm-Up Why can I smell a chocolate bar even though it is a solid? Read the description of the office myster
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Answer:

The smell of a chocolate is from the presence of volatile compounds present in the chocolate bar which at room temperature readily changes phase from solid to liquid to vapor or gas

Explanation:

There are nearly 600 identified compounds present in a chocolate bar and out of these, there are volatile components which gives the chocolate bar its distinctive aroma.

These volatile chocolate contents readily change phase from solid to vapor, with very short duration liquid phase.

For example, 3 methylbutanal, vanillin, and several organic compounds which are known to be readily volatile.

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3 years ago
A stone is tied to a 0.85-meter cord. it is swung in a circle at a constant rate of 6.0 m/s. what is the centripetal acceleratio
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The correct answer is 42. I know this answer is right because i have already turned my assignment in and got it right.
4 0
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How many grams are in 3 mol of KBr?
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Answer: 7

Explanation:

6 0
3 years ago
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what is the balanced equation for the reaction of solid magnesium metal with oxygen gas to produce solid magnesium oxide
GaryK [48]

Answer:

2Mg + O₂ ⟶ 2MgO

Explanation:

Step 1. Start with the most complicated-looking formula (O₂?).

Put a 1 in front of it.

Mg + 1O₂ ⟶ MgO

Step 2. Balance O.

We have fixed 2 O on the left. We need 2O on the right. Put a 2 in front of MgO.

Mg + 1O₂ ⟶ 2MgO

Step 3. Balance Mg.

We have fixed 2 Mg on the right-hand side. We need 2 Mg atoms on the left. Put a 2 in front of Mg.

2Mg + 1O₂ ⟶ 2MgO

Every formula now has a coefficient. The equation should be balanced. Let’s check.

<u>Atom</u>  <u>On the left</u>  <u>On the righ</u>t

  Mg             2                  2

  O                2                  2

All atoms are balanced.

The balanced equation is

2Mg + O₂ ⟶ 2MgO

4 0
3 years ago
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