F(x) sine curve with points at 0, 0 and pi over 2, 4 and pi, 0 and 3 pi over 2, negative 4 and 2 pi,0
g(x) x y 0 0 pi over 2 2 π 0 3 pi over 2 −2 2π 0
h(x) = 2 sin x + 3 Which function has the greatest rate of change on the interval from x = 0 to x = pi over 2
The change of f(x) from 0 to π/2 is 4
The change of g(x) from 0 to π/2 is 2
We can rule out g(x).
As for h(x):
h(0) = 2 sin(0) + 3 = 3
h(π/2) = 2(sin(π/2)) + 3 = 2 + 3 = 5
Change of h(x) from 0 to π/2 is 2.
Greatest change between 0 and π/2 is found with f(x)
It is a acute triangles because the degrees are less than 90 degrees
Answer:
see below
Step-by-step explanation:
1st: x
2nd: 5x + 8
x(5x + 8) = 36
5x² + 8x = 36
5x² + 8x - 36 = 0
(x - 2)(5x + 18) = 0
(x - 2) = 0
x - 2 = 0
x = 2
1st: x = 2
2nd: 5x + 8 = 5(2) + 8 = 18
(5x + 18) = 0
5x + 18 = 0
5x = -18
x = -3.6
1st: x = -3.6
2nd: 5x + 8 = 5(-3.6) + 8 = -18 + 8 = -10
23/6
23 divided by 6 is 3 remainder 5 so it is 3 5/6
Hope this helps :)
