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ladessa [460]
3 years ago
11

Find the kinetic energy of a boy of mass 6.5kg running at a velocity of 6.0m/s​

Chemistry
1 answer:
ololo11 [35]3 years ago
3 0

Explanation:

Given,

M=6.5kg,velocity(v)=6m/s

K.E=1/2mv^2

=1/2×6.5×6^2

=1/2×6.5×36

=18×6.5

=117 J

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6. According to Crystal Field Theory, what should be the color of an aqueous solution of the ion [Y(H2O)6]3
UkoKoshka [18]

Answer:

Colourless

Explanation:

We know that Y^3+ has the electronic configuration of;

1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 (the 5s and 4d levels are empty).

According to the crystal field theory, the colour of complexes result from transitions between incompletely filled d orbitals.

As a result of this, complexes with empty or completely filled d orbitals are colourless. Thus,  [Y(H2O)6]3 is colourless according to the Crystal Field Theory.

4 0
3 years ago
1) If the pressure on 2.6 liters of a gas at 860 Torr is increased to 1000 Torr,
LenKa [72]

2.24 liters is the volume of the gas if pressure is increased to 1000 Torr.

Explanation:

Data given:

Initial volume of the gas V1 = 2.6 liters

Initial pressure of the gas P1 = 860 Torr 1.13 atm

final pressure on the gas P2 = 1000 Torr 1.315 atm

final volume of the gas after pressure change V2 =?

From the data given above, the law used is :

Boyles Law equation:

P1V1 = P2V2

V2 = P1V1/P2

   = 1.13 X 2.6/ 1.31

  = 2.24 Liters

If the pressure is increased to 1000 Torr or 1.315 atm the volume changes to 2.24 liters. Initially the volume was 2.6 litres and the pressure was 860 torr.

6 0
3 years ago
a sample of ideal gas at room temperature occupies a volume of 12.0 L at a pressure of 392 torr. if the pressure changes to 1960
Setler79 [48]
852 x 40.0= 4260 x v2 
<span>v2= 8 L </span>

<span>b) 852 x 40 = p2 x 69.0 </span>
<span>p2= 494 torr</span>
3 0
3 years ago
Hydrogen peroxide decomposes to water and oxygen at constant pressure by the following reaction: 2H2O2(l) → 2H2O(l) + O2(g) ΔH =
Mashcka [7]

<u>Answer:</u> The amount of heat released is -7.203 kJ

<u>Explanation:</u>

The given chemical equation follows:

2H_2O_2(l)\rightarrow 2H_2O(l )+O_2(g);\Delta H=-196kJ

To calculate the enthalpy change for 1 mole of the hydrogen peroxide, we use unitary method:

When 2 moles of hydrogen peroxide is reacted, the enthalpy of the reaction is -196 kJ

So, when 1 mole of hydrogen peroxide will react, the enthalpy of the reaction will be \frac{-196}{2}\times 1=-98kJ

  • To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of hydrogen peroxide = 2.50 g

Molar mass of hydrogen peroxide = 34 g/mol

Putting values in above equation, we get:

\text{Moles of hydrogen peroxide}=\frac{2.50g}{34g/mol}=0.0735mol

  • To calculate the heat of the reaction, we use the equation:

\Delta H_{rxn}=\frac{q}{n}

where,

q = amount of heat released

n = number of moles = 0.0735 moles

\Delta H_{rxn} = enthalpy change of the reaction = -98 kJ/mol

Putting values in above equation, we get:

-98kJ/mol=\frac{q}{0.0735mol}\\\\q=(-98kJ/mol\times 0.0735mol)=-7.203kJ

Hence, the amount of heat released is -7.203 kJ

8 0
3 years ago
How do I graph Charles's law equation?
Blizzard [7]

Answer:

we needa see the equations

3 0
3 years ago
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