All categories

3 years ago

. Never start a job without knowing the _ and ____ of the chemicals you are working with.

Chemistry

2 answers:

pashok25 [27]3 years ago

8 0

Location,types that is your answer for this one hope i helped

LiRa [457]3 years ago

7 0

Answer:

Explanation:

the blanks will be properties and hazard

Working on chemicals can be a dangerous job so before working on chemicals we should have all the knowledge of the chemicals properties.

And also while working on the chemical you should also have the knowledge of the hazard caused by the chemicals.

You might be interested in

Can alkenes react with potassium dichromate

posledela

NO alkenes can not react with potassium dichromate

7 0

3 years ago

What environmental condition is most likely to trigger the closing of leaf stoma? Wind, heat, darkness, or lack of moisture

erma4kov [3.2K]

Lack of moisture :)

8 0

3 years ago

Read 2 more answers

When CO2 decomposes into oxygen and carbon, it gives a gram ratio of 2.67:1 O2:C. When a 32.4g of CO2 decomposes, how many grams

Rufina [12.5K]

Answer : The mass of carbon and oxygen produced is 8.83 g and 23.6 g respectively.

Explanation :

Law of conservation of mass : It states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

The balanced chemical reaction will be,

$CO_2\rightarrow O_2+C$

As we are given:

$\text{Mass of }O_2}:\text{Mass of }C=2.67:1{$

According to the law of conservation of mass,

Total mass of $CO_2$ = Mass of $O_2$ + Mass of C

Total mass of $CO_2$ = 2.67 + 1 = 3.67 g

Now we have to calculate the mass of $O_2$ and C.

$\text{Mass of }O_2=\frac{\text{Given mass of }CO_2}{\text{Total mass of }CO_2}\times \text{Given mass of }O_2=\frac{32.4g}{3.67g}\times 2.67=23.6g$

and,

$\text{Mass of }C=\frac{\text{Given mass of }CO_2}{\text{Total mass of }CO_2}\times \text{Given mass of }C=\frac{32.4g}{3.67g}\times 1=8.83g$

Therefore, the mass of carbon and oxygen produced is 8.83 g and 23.6 g respectively.

6 0

3 years ago

Please help me:( I’ll give u points of its right

goldenfox [79]

Answer:

I believe.. ............

8 0

3 years ago

What is the volume occupied by 4.20 miles of oxygen gas (O2) at STP

Drupady [299]

Answer: 94.13 L

Explanation: In STP in an ideal gas there is a standard value for both temperature and pressure. At STP,pressure is equal to 1atm and the temperature at 0°C is equal to 273.15K. This problem is an ideal gas so we use PV=nRT where R is a constant R= 0.08205 L.atm/mol.K.

To find volume, derive the equation, it becomes V=nRT/P. Substitute the values. V= 4.20 mol( 0.08205L.atm/mol.K)(273.15K) / 1 atm = 94.13 L. The mole units, atm and K will be cancelled out and L will be the remaining unit which is for volume.

8 0

3 years ago

. Never start a job without knowing the ___________ and ______________ of the chemicals you are working with.

. Never start a job without knowing the _ and ____ of the chemicals you are working with.