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SCORPION-xisa [38]
3 years ago
15

Sulfuric acid is a component of acid rain formed when gaseous sulfur dioxide pollutant reacts with gaseous oxygen and liquid wat

er to form aqueous sulfuric acid. part a write a balanced chemical equation for this reaction. express your answer as a chemical equation. identify all of the phases in your answer.
Chemistry
2 answers:
Vesna [10]3 years ago
6 0
2SO₂(g) + O₂(g) + 2H₂O(aq) → 2H₂SO₄(aq)
Igoryamba3 years ago
6 0

Answer:

The chemical reaction is :

2SO_2(g)+O_2(g)+2H_2O(l)\rightarrow 2H_2SO_4(aq)

Explanation:

When sulfur dioxide gas reacts with oxygen gas and liquid water it gives aqueous solution of sulfuric acid.

This is reason behind the acidic nature of the rain water during acid rain.The chemical reaction is given as:

2SO_2(g)+O_2(g)+2H_2O(l)\rightarrow 2H_2SO_4(aq)

According to stoichiometry, 2 moles of sulfur dioxide gas reacts with 1 mole of oxygen gas and 2 moles of water to give 2 moles of aqueous sulfuric acid.

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<u>Answer:</u>

<em>0.264 g of CO_2 can be formed from 288 mg of O_2</em>

<u>Explanation:</u>

The balanced chemical equation is

2 C_3 H_7 OH+9 O_2> 6 CO_2+8 H_2 O

The conversions are  

Mass in mg O_2 is converted to mass in g O_2  

Mass in g O_2 is converted to moles O_2 by dividing with molar mass  

Moles O_2 is converted to moles CO_2  by using the mole ratio of O_2:CO_2 is 9 : 6

Moles CO_2  is converted to mass CO_2 by multiplying with molar mass CO_2

mass in mg O_2  > mass in g O_2 >moles O_2 > moles CO_2 > mass CO_2

288mg O_2 \times \frac{(1g O_2)}{(1000mg O_2 )} \times \frac {(1molO_2)}{(32gO_2 )}\times\frac {(6mol CO_2)}{(9mol O_2 )} \times \frac {(44.0 gCO_2)}{(1mol CO_2 )}

=0.264g (Answer)

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