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SCORPION-xisa [38]
3 years ago
15

Sulfuric acid is a component of acid rain formed when gaseous sulfur dioxide pollutant reacts with gaseous oxygen and liquid wat

er to form aqueous sulfuric acid. part a write a balanced chemical equation for this reaction. express your answer as a chemical equation. identify all of the phases in your answer.
Chemistry
2 answers:
Vesna [10]3 years ago
6 0
2SO₂(g) + O₂(g) + 2H₂O(aq) → 2H₂SO₄(aq)
Igoryamba3 years ago
6 0

Answer:

The chemical reaction is :

2SO_2(g)+O_2(g)+2H_2O(l)\rightarrow 2H_2SO_4(aq)

Explanation:

When sulfur dioxide gas reacts with oxygen gas and liquid water it gives aqueous solution of sulfuric acid.

This is reason behind the acidic nature of the rain water during acid rain.The chemical reaction is given as:

2SO_2(g)+O_2(g)+2H_2O(l)\rightarrow 2H_2SO_4(aq)

According to stoichiometry, 2 moles of sulfur dioxide gas reacts with 1 mole of oxygen gas and 2 moles of water to give 2 moles of aqueous sulfuric acid.

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Balance the following chemical equation.<br><br> CCl4 -&gt; ___ C+ ___ Cl2
Bingel [31]

Answer:

Explanation:

CCl4 => C + 2Cl2

6 0
2 years ago
a 125 g chunk of aluminum at 182 degrees Celsius was added to a bucket filled with 365 g of water at 22.0 degrees Celsius. Ignor
Diano4ka-milaya [45]
<h3>Answer:</h3>

32.98°C

<h3>Explanation:</h3>

We are given the following;

Mass of Aluminium as 125 g

Initial temperature of Aluminium as 182°C

Mass of water as 265 g

Initial temperature of water as 22°C

We are required to calculate the final temperature of the two compounds;

First, we need to know the specific heat capacity of each;

Specific heat capacity of Aluminium is 0.9 J/g°C

Specific heat capacity of water is 4.184 J/g°C

<h3>Step 1: Calculate the Quantity of heat gained by water.</h3>

Assuming the final temperature is X°C

we know, Q = mcΔT

Change in temperature, ΔT = (X-22)°C

therefore;

Q = 365 g × 4.184 J/g°C × (X-22)°C

    = (1527.16X-33,597.52) Joules

<h3>Step 2: Calculate the quantity of heat released by Aluminium </h3>

Using the final temperature, X°C

Change in temperature, ΔT = -(X°- 182°)C (negative because heat was lost)

Therefore;

Q = 125 g × 0.90 J/g°C × (182°-X°)C

  = (20,475- 112.5X) Joules

<h3>Step 3: Calculating the final temperature</h3>

We need to know that the heat released by aluminium is equal to heat absorbed by water.

Therefore;

(20,475- 112.5X) Joules = (1527.16X-33,597.52) Joules

Combining the like terms;

1639.66X = 54072.52

             X = 32.978°C

                = 32.98°C

Therefore, the final temperature of the two compounds will be 32.98°C

7 0
3 years ago
When a 3.00 g 3.00 g sample of KBr KBr is dissolved in water in a calorimeter that has a total heat capacity of 1.36 kJ ⋅ K − 1
cupoosta [38]

Answer:

Molar heat of solution of KBr is 20.0kJ/mol

Explanation:

Molar heat of solution is defined as the energy released (negative) or absorbed (Positive) per mole of solute being dissolved in solvent.

The dissolution of KBr is:

KBr → K⁺ + Br⁻

In the calorimeter, the temperature decreases 0.370K, that means the solution absorbes energy in this process. The energy is:

q = 1.36kJK⁻¹ × 0.370K

q = 0.5032kJ

Moles of KBr in 3.00g are:

3.00g × (1mol / 119g) = 0.0252moles

Thus, molar heat of solution of KBr is:

0.5032kJ / 0.0252moles = <em>20.0kJ/mol</em>

3 0
3 years ago
Name 3 sources of carbohydrates for the production of an alcoholic drink
icang [17]

Answer:An alcoholic drink is a drink that contains ethanol, a type of alcohol produced by fermentation of grains, fruits, or other sources of sugar. The consumption of alcohol plays an important social role in many cultures. Most countries have laws regulating the production, sale, and consumption of alcoholic beverages.

Explanation: vodka the preferred alcoholic beverage of choice among alcoholics? #3 Doesn't make you feel bloated or full like beer does. It goes down quickly and smooth. #4 Gets you drunk just as fast as any other hard liquor can, and obviously much faster than beer or wine.

4 0
3 years ago
How many liters of carbon dioxide can be produced if 37.8 grams of carbon disulfide react with excess oxygen gas at 28.85 degree
alekssr [168]
37.8 grams of CS2 equals to 37.8/76=0.5 mole. So the products have 0.5 mole CO2 which is 11.2 liters at STP. So according to the gas law, the volume at given condition is 12.4 liters. So the answer should be 12.2 liters.
8 0
2 years ago
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