Answer:
Cat with 6 kg sitting on a 30 meter hill has greater potential energy.
Explanation:
gravitational potential energy (J) = mass (kg) × gravitational field × height (m)
<h3 /><h3><u>Note</u>:</h3>
gravitational field in Earth is 10 N/kg = <u>fixed unit</u>
<h3 /><h3><u>Given</u>:</h3>
1st Cat: 4 kg
2nd Cat: 6 kg
Both of their height is 30 meters.
<h3><u>Solve for g.p.e</u>:</h3>
1st cat = mgh = 4 × 10 × 30 = 1200 Joules
2nd cat = mgh = 6 × 10 × 30 = 1800 Joules
A student uses a meter to measure 120 coulombs flowing through a circuit in 60 seconds. The electric current in this circuit will be 2 A
Current is a flow of electrical charge carriers, usually electrons or electron-deficient atoms. The common symbol for current is the uppercase letter I. The standard unit is the ampere, symbolized by A.
current = charge / time
given
time = 60 seconds
charge = 120 Coulombs
current = Q / T = 120 / 60 = 2 A
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Answer:
Force of friction, f = 751.97 N
Explanation:
it is given that,
Mass of the car, m = 1100 kg
It is parked on a 4° incline. We need to find the force of friction keeping the car from sliding down the incline.
From the attached figure, it is clear that the normal and its weight is acting on the car. f is the force of friction such that it balances the x component of its weight i.e.
f = 751.97 N
So, the force of friction on the car is 751.97 N. Hence, this is the required solution.
Answer: The dog is pull the stick away from the boys hand
the boy is also pulling if the boy lets go of the stick the dog will fall due to law of action and reaction
The man is pushing the horse cart up the hill to do so he has to apply force
Explanation:
