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babymother [125]
3 years ago
9

block of mass m sits at rest on a rough inclined ramp that makes an angle with the horizontal. What must be true about normal fo

rce F on the block due to the ramp
Physics
1 answer:
oee [108]3 years ago
6 0

Answer:

Explanation:

For a body on a ramp with mass m, the forces acting on the body along the vertical component are the weight and the normal reaction.

The weight of the body acts in the negative y direction while the normal reaction acts in the positive y direction

Taking the sum of forces along the y component

Sum Fy = -W+R = ma

Since acceleration is zero

-W+R = m(0)

-W+R = 0

-W = -R

W = R

Hence the Normal reaction force acting on the on the body is equal to normal force

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An electron has a kinetic energy of 3.00 ev. find its wavelength. (b) what if? a photon has energy 3.00 ev. find its wavelength.
Harman [31]
(a) The electron kinetic energy is
K=3.00 eV
which can be converted into Joule by keeping in mind that
1 eV=1.6 \cdot 10^{-19}eV
So that we find
K=3.00 eV \cdot 1.6 \cdot 10^{-19} eV/J =4.8 \cdot 10^{-19}J

The kinetic energy of the electron is related to its momentum p by:
K= \frac{p^2}{2m}
where m is the electron mass. Re-arranging the equation, we find
p= \sqrt{ 2Km}= \sqrt{ 2  ( 4.8 \cdot 10^{-19} J)(9.1 \cdot 10^{-31} kg) } =9.35 \cdot 10^{-25} kgm/s

And now we can use De Broglie's relationship to find its wavelength:
\lambda= \frac{h}{p}= \frac{6.6 \cdot 10^{-34} Js}{9.35 \cdot 10^{-25} kg m/s} =7.06 \cdot 10^{-10}m
where h is the Planck constant.


(b) By using the same procedure of part (a), we can convert the photon energy into Joules:
E=3.00 eV \cdot 1.6 \cdot 10^{-19} eV/J =4.8 \cdot 10^{-19}J

The energy of a photon is related to its frequency f by:
E=hf
where h is the Planck constant. Re-arranging the equation, we find
f= \frac{E}{h}= \frac{4.8 \cdot 10^{-19} J}{6.6 \cdot 10^{-34}Js} =7.27 \cdot 10^{14}Hz

And now we can use the relationship between frequency f, speed of light c and wavelength \lambda of a photon, to find its wavelength:
\lambda= \frac{c}{f}= \frac{3 \cdot 10^8 m/s}{7.27 \cdot 10^{14} Hz} =4.13 \cdot 10^{-7} m
8 0
3 years ago
CAN SOMEONE PLEASE HELP ME!!?<br> I NEED HELP PLEASE!!
Dmitry [639]
The first one is decreases because there are less molecules in the air.
The second on would be the last option, August 29, because a new moon occurs every 29 days.
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3 0
3 years ago
What is the distance from the earth's center to a point outside the earth where the gravitational acceleration due to the earth
Crazy boy [7]
R2^ 2 / R1 ^2 = g1 / g2 = 38 

<span>R2 = R1 x √38 = 6.1644* R1 </span>

<span>R2 = 6.1644 x 6378 000 = 39316632.5 m</span>
8 0
3 years ago
A student wants to determine the effect of mass on kinetic energy. She will drop two balls of the same size into a pool of water
Anastasy [175]

Answer:

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Explanation:

4 0
2 years ago
What is the momentum of a 5 kg object that has a velocity of 1.2 m/s? 3.8 kg • m/s 4.2 kg • m/s 6.0 kg • m/s 6.2 kg • m/s
Gnesinka [82]

Answer:

Your answer will be 6.0kg•m/s

Explanation:

In the given question all the required details d given. Using these information's a person can easily find the momentum of the object. In the question it is already given that the mass of the object is 5 kg and the velocity at which it is traveling is 1.2 m/s.We know the equation of finding momentum asMomentum = mass * velocity                   = 5 * 1.2                    = 6So the momentum of the object is 6 Newton.

4 0
3 years ago
Read 2 more answers
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