Answer:
27
Step-by-step explanation:
3x3= 9 9x 3 = 27
Total= 27
if this is not right im sorry
11 pls mark me brainliest
First find the slope of this new line; it's the same as the slope of the "given line," which you unfortunately have not yet given. Let's call that slope "m."
Then, the equation in point-slope form of the new line is
y - (-1) = m(x - [-1]), or y+1 = m(x+1)
Please go back to the original question, obtain the slope of the "given line," and substitute that value for m in y+1 = m(x+1).
5(-2a-8) < -9a + 4
Use distributive property on left side:
-10a -40 < -9a + 4
Add 40 to both sides
-10a < -9a + 44
Add 9a to both sides
-a < 44
Multiply both sides by -1 and reverse the inequality sign:
A > -44
Answer: a > -44
Answer:
In set-builder notation, the set of solutions is:
![\left \{u|-3](https://tex.z-dn.net/?f=%5Cleft%20%5C%7Bu%7C-3%3Cu%3C7%5Cright%5C%7D)
Step-by-step explanation:
Let's start by isolating the absolute value expression on one side of the inequality:
8 | u - 2 | - 7 < 33
add 7 on both sides:
8 | u - 2 | < 40
divide both sides by 8:
| u - 2 | < 5
Now, in order to remove the absolute value symbols, we need to consider two different cases:
1) what is inside the absolute value symbols is larger than or equal to zero, so in such case when we remove the absolute value we get exactly what was inside:
u - 2 < 5
u < 5 + 2
u < 7
Now the other case;
2) what is inside the absolute value is smaller than zero, then when removing the symbols we get:
2 - u < 5
2 - 5 < u
-3 < u
Then the set of solutions of this inequality are the set of u values such that u is larger than -3 (to the right of -3 on the number line, and smaller than 7 (to the left of the number 7 on the number line.
In graph form this should look like a highlighted segment on the number line that starts at -3 on the left, ends at 7 on the right, and doesn't include the endpoints -3 and 7.
in set builder notation, the set of solutions is given by:
![\left \{u|-3](https://tex.z-dn.net/?f=%5Cleft%20%5C%7Bu%7C-3%3Cu%3C7%5Cright%5C%7D)