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Serggg [28]
3 years ago
6

A 70-kg boy is sitting 3 m from the ground in a tree. What is his gravitational potential energy

Physics
1 answer:
steposvetlana [31]3 years ago
7 0

m x h x 9.8 m/s squared

70 kg x 3 m x 9.8 m/s squared= 2058 Joules

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A cat is on a 1.5 m high table and jumps at a 37 angle with a speed of 10 m/s. how far horizontally from the edge of the table d
Kaylis [27]
The answer is 11.51 meters (:
8 0
3 years ago
an object of mass 6000 kg rests on the flatbed of a truck. it is held in place by metal brackets that can exert a maximum horizo
Otrada [13]

Answer:

minimum stopping distance will be d = 75 m

Explanation:

Maximum force exerted by the bracket is given as

F = 9000 N

now we know that mass of the object is

m = 6000 kg

so the maximum acceleration that truck can have is given as

F = ma

9000 = 6000 a

a = 1.5 m/s^2

now for finding minimum stopping distance of the truck

v_f^2 - v_i^2 = 2a d

0^2 - 15^2 = 2(-1.5) d

d = 75 m

4 0
3 years ago
How are climate and weather related?
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Weather is what conditions of the atmosphere are over a short period of time, and climate is how the atmosphere "behaves" over relatively long periods of time.
8 0
3 years ago
Why do you think the outer planets have such extensive systems of rings and moons, while the inner planets do not?
Inessa05 [86]

Answer:

Because of immense gravity

Explanation:

The formation of the Solar system was a very dynamic process. A lot of matter was thrown towards the outer solar system which further formed the Gas giants: Jupiter, Saturn, Uranus, and Neptune. The size of these outer planets is huge so is their gravity.

Because of their huge gravity a lot of matter which was scattered in the outer solar system got attracted towards them. This matter is what make the rings of the outer planets. Also, because of immense gravity they captured larger bodies thus making them their Moons.

6 0
2 years ago
What magnification will be produced by a lens of power –4.00 D (such as might be used to correct myopia) if an object is held 43
kiruha [24]

Answer:

The magnification is m  = 0.3674

Explanation:

From the question we are told that

  The  power of the lens is  P = -4.00 D(dioptre)

Generally  1 dioptre = 1 \ meter

  The object distance is u =  -43 \ cm the negative sign is because the distance is measured in the opposite direction of incident light (i.e away )

 Generally the focal length is mathematically represented as

          f = \frac{1}{P}  

   =>f = \frac{1}{4.00 }  

  =>  f = 0.25 \ m

converting to  cm  

 =>   f = 0.25 \ m = 0.25 * 100 = 25 \ cm

Generally from lens equation  we have that  

     \frac{1}{f} +\frac{1}{v} -\frac{1}{u}

=>  \frac{1}{25} +\frac{1}{v} -\frac{1}{-43}

=>   v =  -15.8 \ cm

Generally the magnification is mathematically represented as

      m  = \frac{v}{u}

=>    m  = \frac{- 15.8}{-43}

=>    m  = 0.3674

6 0
2 years ago
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