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mart [117]
3 years ago
15

Miguel's parents drove him to a track meet that was 305 km away from the school. It took them 3 hours, which included a 30 minut

e break for breakfast. What was their average speed?
A.101.7 km/h
B.915 km/
C.122 km/h
D.275 km/h
Physics
1 answer:
OverLord2011 [107]3 years ago
6 0
A., 101.7 km/h is the correct answer for this question
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The tendency of two masses alone in the universe to drift together is a result of
torisob [31]
It is as a result of gravity.  (D)

This is as stated by Newton's law of universal gravitation. That two objects in the universe attract one another with a force that is proportional to the product of their masses and inversely proportional to the square of the distance apart.

The constant of proportionality is the Universal Gravitational Constant.

G = 6.673 × 10⁻¹¹ Nm²kg⁻²
4 0
3 years ago
Read 2 more answers
On sunday a strong gale blows near beth’s house. the best estimate for the wind speed is ____ miles/hour.
Rufina [12.5K]

Answer:

B. 47-54 miles/hour

Explanation:

Gale is a strong wind which is depicted by red warning flag. According to U.S. National Weather Service gale is a sustained surface wind. It is also used to refer winds from tropical coastal areas.

On the basis of force of wind gale is divided in four groups:

  1. Near gale   - 32-38 mph
  2. Gale            - 39-46 mph
  3. Strong gale - 47-54 mph
  4. Storm           - 55-63 mph
8 0
4 years ago
The work energy principle states that the change in kinetic energy of an object is equal to the net work done on the object. If
sattari [20]

Answer:

v=\sqrt{2gh}\ m/s

Explanation:

From work energy theorem

Work done by all forces = Change in kinetic energy

Lets take

m= mass of object

h=height from the ground surface

initial velocity of object = 0 m/s

The final velocity of object is v

Work done by gravitational force = m g . h

The final kinetic energy = 1/2 m v²

So

Work done by all forces = Change in kinetic energy

m g h =  1/2 m v² - 0

v² = 2 g h

v=\sqrt{2gh}\ m/s

6 0
3 years ago
In a wire with a 1.05 mm2 cross-sectional area, 7.93×1020 electrons flow past any point during 3.97 s. What is the current ????
34kurt

Answer:

The current in the wire is 31.96 A.

Explanation:

The current in the wire can be calculated as follows:

I = \frac{q}{t}

<u>Where</u>:

q: is the electric charge transferred through the surface

t: is the time      

The charge, q, is:

q = n*e

<u>Where</u>:

n: is the number of electrons = 7.93x10²⁰

e: is the electron's charge = 1.6x10⁻¹⁹ C

q = n*e = 7.93 \cdot 10^{20}*1.6 \cdot 10^{-19} C = 126.88 C

Hence, the current in the wire is:

I = \frac{126.88 C}{3.97 s} = 31.96 A

Therefore, the current in the wire is 31.96 A.

I hope it helps you!

3 0
3 years ago
Dallas says that any change in velocity is directly proportional tothe time interval over which the change took place. Dana says
Anna35 [415]

Answer:

e. Only(a) and (b) above are correct

Explanation:

Impulse

= Fx t = m ( v-u )

v-u = change in velocity

F x t = mass x change in velocity

change in velocity = F t / mass

=a t

change in velocity ∝ t ( time ) , if a is constant

dv = a_avg  dt

∫dv = a_avg ∫dt

v-u = a_avg t

change in velocity ∝ t ( time )

So both (a) and (b) are correct.

7 0
3 years ago
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