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andrezito [222]
3 years ago
13

if a bus has a mass of 5000 kg and a velocity of 10 m/s, what must the velocity of a 1500 kg can be to have the same momentum

Physics
1 answer:
fgiga [73]3 years ago
6 0

Answer:

qeyygrydfguygffsddtggfxccfufdrfff

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When the distance between two stars decreases by one-third, the force between them
pashok25 [27]

Answer:

the force will increase by a factor 2.25

Explanation:

The gravitational force between the two stars is given by:

F=G\frac{m_1 m_2}{r^2}

where

G is the gravitational constant

m1, m2 are the masses of the two stars

r is the distance between the stars

If the distance is decreased by one-third, it means that the new distance is 2/3 of the previous distance

r'=\frac{2}{3}r

So the new force will be

F'=G\frac{m_1 m_2}{(\frac{2}{3}r)^2}=\frac{9}{4} G\frac{m_1 m_2}{r^2}=2.25 F

So, the force will be 2.25 times the previous value.

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4 years ago
Levi and Clara are trying to move a very heavy box. Levi is pushing the box with a force of 30 N, and Clara is pulling the box w
Komok [63]
There is a ner force of 15 N allowing Levi and Clara to mobe the box.
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3 years ago
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Prove the correctness of this equation s=vt + 1/2at ​
Kaylis [27]

Answer:

The formula is dimensionally correct.

Explanation:

Given

s = ut + \frac{1}{2}at^2

Required

Prove its correctness

Write out the dimension of each:

s = M^0LT^0 --- displacement

ut = M^0LT^{-1} *  T --- velocity * time

\frac{1}{2}at^2 = M^0LT^{-2} * T^2 --- acceleration * square of time

The expression becomes:

s = ut + \frac{1}{2}at^2

M^0LT^0 = M^0LT^{-1} *  T + M^0LT^{-2} * T^2

Apply law of indices

M^0LT^0 = M^0LT^{-1+1} + M^0LT^{-2+2}

M^0LT^0 = M^0LT^{0} + M^0LT^{0}

M^0LT^0 = M^0LT^{0}

Both sides of the equation are equal

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Fill in the blank
nignag [31]

Answer:

temperature

Explanation:

when you put a water on the stove the water will start to boil there for temperature

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