do not obey ohm's law so it's a I believe
Answer:
answer is option d
Explanation:
just took unit test edg 2021
Answer:

Explanation:
Given data
Space vehicle speed=5425 km/h relative to earth
The rocket motor speed=81 km/h and mass 4m
The command has mass m
From the conservation of momentum as the system isolated

Since the motion in on direction we can drop the unit vector direction

Where M is the mass of space vehicle which equals to sum of the motors mass and command mass.
The velocity of the motor relative to the earth equals the velocity of the motor relative to command plus the velocity of the command relative to earth

Where Vmc is the velocity of motor relative to command
This yields

Substitute the given values
Answer:
124.88 km/h
34.69 m/s
Explanation:
1633.8 km = 1633800 m
13 hours 4 minutes 58 seconds = 13 + 4/60 + 58/3600 = 13.083 hours
13 hours 4 minutes 58 seconds = 13*3600 + 4*60 + 58 = 47098 seconds
So the average speed in km/h is
1633.8 / 13.083 = 124.88 km/h
The average speed in m/s is
1633800 / 47098 = 34.69 m/s