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Nostrana [21]
3 years ago
8

Referring to the sketch of a planet around the sun, Area A is three times that of Area B. Compare the times required for the pla

net to travel from Point 1 to Point 2 and from Point 3 to Point 4 and select the letter of the correct answer.

Physics
2 answers:
charle [14.2K]3 years ago
4 0

Answer:

tA is three times tB

Explanation:

liq [111]3 years ago
3 0

tA is three times tB

Referring to the sketch of a planet around the sun, Area A is three times that of Area B. Compare the times required for the planet to travel from Point 1 to Point 2 and from Point 3 to Point 4 and select the letter of the correct answer.

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An unknown substance has a mass of 670 kg and a volume of 782 m^3. Will it float in water? (Water has a density of 1,000 kg/m^3.
matrenka [14]

Answer:

It will float

Explanation:

its density is lower than density of water

Its density is 670 / 782 = 0.856 kg/m³

6 0
3 years ago
Para fabricar la bicicleta de un niño pequeño se tiene en cuenta que la fuerza que puede desarrollar es menor que la de un adult
Georgia [21]

Answer:

a) El piñón debe tener 20 dientes.

b) La bicicleta avanza aproximadamente 1,759 metros por cada pedaleada completa.

Explanation:

a) El plato es el engranaje más grande que forma parte del sistema de transmisión, acompañando a la cadena y el piñón integrado a la rueda trasera. Asumiendo que no existen pérdidas por fricción seca y que las condiciones de lubricación del sistema de transmisión son óptimas tal que las pérdidas de potencia son despreciables. Además, supongamos que la bicicleta viaja a velocidad constante, entonces tenemos la siguiente identidad mediante las definiciones de trabajo y potencia:

T_{P}\cdot \omega_{P} = T_{p}\cdot \omega_{p} (1)

Donde:

T_{P} - Torque del plato, en newton-metros.

T_{p} - Torque del piñón, en newton-metros.

\omega_{p} - Rapidez angular del piñón, en radianes por segundo.

\omega_{P} - Rapidez angular del plato, en radianes por segundo.

Sabiendo el hecho que tanto el plato y el piñón experimenta la misma velocidad tangencial, podemos simplificar (1) como sigue:

\frac{T_{P}}{R_{P}} = \frac{T_{p}}{R_{p}} (1b)

Puesto que el radio de cada elemento y el número de dientes son, por separado, directamente proporcionales al número de dientes, modificamos (1b) así y tenemos la siguiente identidad, la cual equivale a su vez a la razón de desarrollo:

\frac{T_{P}}{T_{p}} = \frac{N_{P}}{N_{p}} = \frac{R_{P}}{R_{p}} = \frac{\omega_{p}}{\omega_{P}} (1c)

Donde:

N_{p} - Número de dientes del piñón, sin unidad.

N_{P} - Número de dientes del plato, sin unidad.

Si tenemos que r = 1,4 y N_{P} = 28, entonces tenemos que el número de dientes del piñón es:

r = \frac{N_{P}}{N_{p}}

N_{p} = \frac{N_{P}}{r}

N_{p} = \frac{28}{1,4}

N_{p} = 20

El piñón debe tener 20 dientes.

b) De acuerdo con la relación de desarrollo, por cada revolución realizada por el plato, el piñón realiza 1,4 revoluciones. Entonces, el avance realizado por la rueda trasera (s), en metros, es igual al productor de la relación de desarrollo y la circunferencia de la rueda, es decir:

s = r\cdot 2\pi\cdot R (1)

Donde R es el radio de la rueda trasera, en metros.

Si conocemos que r = 1,4 y R = 0,2\,m, entonces el avance realizado por la rueda trasera es:

s = r\cdot 2\pi\cdot R

s = (1,4)\cdot (2\pi)\cdot (0,2\,m)

s \approx 1,759 \,m

La bicicleta avanza aproximadamente 1,759 metros por cada pedaleada completa.

3 0
3 years ago
A 400 hp engine in a 1,600 kg car applies maximum force for 2 seconds to accelerate the car onto the
babymother [125]

Answer:

I will assume that “maximum force” implies the constant application of power  P  = 400 hp (international) to accelerating the vehicle. The force will therefore vary with speed as the vehicle accelerates. I will also assume that all engine energy goes into accelerating the vehicle, rather than rotating elements like its wheels.

In this case the 400 hp (equivalent to 298,280 watts) is applied for time  t  = 2 seconds. Therefore the kinetic energy of the vehicle is increased by:

ΔKE=Pt=(298,280)(2)=596,560  joules.

The initial kinetic energy is:

KEinitial=12mv2

=(0.5)(1600)(82)=51,200  joules.

Therefore final kinetic energy is:

KEfinal=KEinitial+ΔKE

=51,200+596,560

=647,760  joules

Therefore final vehicle velocity can be found:

KEfinal=12mv2

v=2KEfinalm−−−−−−−−√

=(2)(647,760)1600−−−−−−−−−−−√

= 28.455 m/s

Explanation:

4 0
3 years ago
Which image depict electrons moving so that each element has a stable noble-gas electron configuration ?
vitfil [10]
The fact I can get is c and d
5 0
4 years ago
A spring (k = 200 N/m) is fixed at the top of a frictionless plane inclined at angle θ = 33 °. A 1.2 kg block is projected up th
Serga [27]

Answer:

Explanation:

Initial kinetic energy = 29 J

work done against gravity = mgsin33 x d  , m is mass of the block

= 1.2 x 9.8 sin 33 x .9

= 5.76 J

potential energy stored in compressed spring

= 1/2 k x², k is spring constant and x is compression

= .5 x 200 x .3²

= 9

energy left = 29 - ( 5.76 + 9 )

= 14.24 J

b )

energy stored in spring when compression is .4 m

= 1/2 x 200 x .4²

= 16 J

required kinetic energy = 16 + 5.76

= 21.76 J

Block must be projected with energy of 21.76 J .

7 0
3 years ago
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