The temperature of the wind as that decreases the volume and the pressure of the balloon to the given values is 14.09°C.
<h3>What is Combined gas law?</h3>
Combined gas law put together both Boyle's Law, Charles's Law, and Gay-Lussac's Law. It states that "the ratio of the product of volume and pressure and the absolute temperature of a gas is equal to a constant.
It is expressed as;
P₁V₁/T₁ = P₂V₂/T₂
Given the data in the question;
- Initial volume V₁ = 14.5L
- Initial pressure P₁ = 0.980atm
- Initial temperature T₁ = 20.0°C = 293.15K
- Final pressure P₂ = 740.mmHg = 0.973684atm
We substitute our given values into the expression above.
P₁V₁/T₁ = P₂V₂/T₂
( 0.980atm × 14.5L )/293.15K = ( 0.973684atm × 14.3L )/T₂
14.21Latm / 293.15K = 13.92368Latm / T₂
14.21Latm × T₂ = 13.92368Latm × 293.15K
14.21Latm × T₂ = 4081.72679LatmK
T₂ = 4081.72679LatmK / 14.21Latm
T₂ = 287.24K
T₂ = 14.09°C
Therefore, the temperature of the wind as that decreases the volume and the pressure of the balloon to the given values is 14.09°C.
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Answer:
74 litre
Explanation:
using ideal gas eqation PV=nRT
here P(pressure)=81.8 kPa =81.8×10^3 Pa
moles=2.5
temperature=273.15+18=291.15K
Gas constant R=8.314m^3-Pa/K-mol
now, V=nRT/P = 8.314×2.5×291.5/81.8×10^3 ≈74litre
✌️;)
Answer:
As potassium chloride (KCl) dissolves in water, the ions are hydrated. ... Ion-dipole forces attract the positive (hydrogen) end of the polar water molecules to the negative chloride ions at the surface of the solid, and they attract the negative (oxygen) ends to the positive potassium ions.
In nuclear fission heavier elements are split to make lighter elements whilst releasing energy. An atom, its nucleus to be more specific, is bombarded with neutrons. The nucleus becomes unstable and it starts to split/decay. It creates the fusion products. Neutrons and lighter elements are released; the neutrons from the nuclei of the atom(s) being split.
