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Sever21 [200]
4 years ago
11

What is the difference between a 1s orbital and a 2s orbital is that

Chemistry
1 answer:
iVinArrow [24]4 years ago
4 0

Answer:

The main difference is their energy level, 2s orbital is higher than 1s orbital.

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Student A performed gravimetric analysis for sulfate in her unknown using the same procedures we did . Results of her three tria
soldi70 [24.7K]

Answer:

The answer is Sodium Sulfate = Na2SO4  

Explanation:

Molar mass of sulfate = 1 (S) + 4 (O) = 1 (32) + 4 (16) = 32 + 64 = 96  

Molar mass of sodium sulfate = 2 (23) + 96 = 46 + 96 = 142  

% of Sulfate = (96/142)*100 = 67.6%  

Percent mistake in Studen A,  

(I) % mistake = (67.6 - 68.6)/67.6 = 1.48  

(ii) % mistake = (67.6 - 66.2)/67.6 = 2.07  

(iii) % mistake = (67.6 - 67.1)/67.6 = 0.74  

For understudy B  

(I) % mistake = (67.6 - 66.7)/67.6 = 1.33  

(ii) % mistake = (67.6 - 66.6)/67.6 = 1.48  

(iii) % mistake = (67.6 - 66.5)/67.6 = 1.63  

Sutdent An is some how exact.  

Understudy B is exact however not precise.

8 0
4 years ago
NO GUESSING!ONLY RIGHT ANSWER
lutik1710 [3]
<h3> <u>ANSWER</u></h3>

2. Neon, only

<h3><u>EXPLANATION</u></h3>

When Na and F combine they form an electron configuration of 2-8. Na electron configuration is 2-8-1 while F is 2-7, so when they form an ionic bond F will gain Na outermost electron to complete its valence shell due to having a higher negativity. Neon has an electron configuration of 2-8 but argon has 2-8-8.

7 0
3 years ago
g Five calcite, CaCO3 (MW 100.085 g/mol), samples of equal mass have a total mass of 12.3±0.1 g. What is the absolute uncertaint
diamong [38]

Answer:

The value  is   L  =  0.985 \pm 0.00801 \  g

Explanation:

From the question we are told that

  The  molar mass of CaCO_3 is  MW  =  100.085 \  g/mol

   The  total mass is  m_g  = 12.3 \ g

   The uncertainty of the total mass is \Delta g  = 0.1

Generally the molar weight of calcium is M_c  =  40 g/mol

 The percentage of calcium in calcite is mathematically represented as

          C =  \frac{40.07}{100.085} * 100

          C =  40.03 \%

Generally the mass of each sample is mathematically represented as

     m=  \frac{m_g}{5}

     m=  \frac{12.3}{5}

     m= 2.46 \  g

Generally mass of calcium present in a single sample is mathematically represented as

        m_c = 2.46 *  \frac{40.04}{100}

       m_c = 0.985 \  g

The  uncertainty of  mass of a single sample is mathematically represented as

      k  =  \frac{\Delta g }{5}

        k  =  \frac{0.1 }{5}

       k  =  0.02\  g

The  uncertainty of  mass of calcium in a single sample is mathematically represent

         G  =  \frac{0.02 *  40.04}{ 100}

          G  =  0.00801 \  g

Generally the average mass of calcium in each sample is  

          L  =  0.985 \pm 0.00801

6 0
3 years ago
How many moles of gold are there in 14.2×1023 atoms of gold?
timofeeve [1]

Answer : The correct answer is 2.36 mol of gold

1 mole of any element have 6.022 x 10²³ number of atoms ( Avogadro's number).

So the formula relating mole and number of atoms is given as :

Mole = \frac{given number of atom }{ 6.022 * 10^2^3 atom}    * 1 mol

Plugging value in formula :

Mole = \frac{14.2 *10^2^3 }{6.022 x10^2^3}   * 1 mol

Mole of gold = 2.36 mol

4 0
4 years ago
Read 2 more answers
The so-called Livestock Evolution involves increased consumption of animal products in developing countries.
Rama09 [41]
This is probably true but I’m not 100% sure
4 0
3 years ago
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