Answer:
(3) 345 nm
Explanation:
<u>Given:</u>
Average C-C bond energy = 347 kJ/mol
<u>To determine:</u>
Wavelength of photon that can break a C-C bond
<u>Calculation:</u>
The energy (E) of a photon is related to its wavelength (λ) by the Planck's equation:
where h = Planck's constant = 6.626*10⁻³⁴ Js
c = speed of light = 3*10⁸ m/s
λ = 3.45*10⁻⁷ m
Since 1 nanometer (nm) = 10⁻⁹ m
The calculated wavelength corresponds to 345 nm
Answer:
9. 8.2x10¹⁴ Hz
Explanation:
Wavelength λ = 366 nm
Formula: Frequency = C / λ
To find the wavelength in m,
1 nm = 1.0x10⁻⁹ m
So, 366 nm = ?
= 3.66x10⁻⁷ m
Frequency = 3.0x10⁸m.s-1 / 3.66x10⁻⁷ m
= 8.2x10¹⁴ s-1
Answer:
It's true :) Hope that helps
Answer:
35Cl = 75.9 %
37Cl = 24.1 %
Explanation:
Step 1: Data given
The relative atomic mass of Chlorine = 35.45 amu
Mass of the isotopes:
35Cl = 34.96885269 amu
37Cl = 36.96590258 amu
Step 2: Calculate percentage abundance
35.45 = x*34.96885269 + y*36.96590258
x+y = 1 x = 1-y
35.45 = (1-y)*34.96885269 + y*36.96590258
35.45 = 34.96885269 - 34.96885269y +36.96590258y
0.48114731 = 1,99704989y
y = 0.241 = 24.1 %
35Cl = 34.96885269 amu = 75.9 %
37Cl = 36.96590258 amu = 24.1 %
