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Molodets [167]
3 years ago
14

What is the energy of a photon of yellow light with a frequency of 5.2 x 10¹⁴ Hz?​

Chemistry
1 answer:
3241004551 [841]3 years ago
4 0

Answer:

3.4x10⁻¹⁹J is the energy of the photon

Explanation:

To find the energy of a photon from its frequency we must use the equation:

E = hf

<em>Where E is the energy of the photon in J, our incognite</em>

<em>h is Planck's constant = 6.6262x10⁻³⁴Js</em>

<em>And f is the frequency = 5.2x10¹⁴Hz = 5.2x10¹⁴s⁻¹</em>

<em />

Replacing:

E = 6.6262x10⁻³⁴Js*5.2x10¹⁴s⁻¹

E = 3.4x10⁻¹⁹J is the energy of the photon

<em />

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Physical changes are when things get changed without altering chemical consistencies, which is melting solid butter into liquid one, or boiling water. Chemical changes are things such as caramelizing sugar when making sweets, or when carbon dioxide is created and released when baking bread.
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Vitamin C contains the elements C, H, and O. It is known to contain 40.9% C and 4.58% H by mass. The molar mass of vitamin C has
soldier1979 [14.2K]

Answer:

C₆H₈O₆

Explanation:

First off, the<u> percent of oxygen by mass</u> of vitamin C is:

  • 100 - (40.9+4.58) = 54.52 %

<em>Assume we have one mol of vitamin C</em>. Then we would have <em>180 grams</em>, of which:

  • 180 * 40.9/100 = 73.62 grams are of Carbon
  • 180 * 4.58/100 = 8.224 grams are of Hydrogen
  • 180 * 54.52/100 = 98.136 grams are of Oxygen

Now we <u>convert each of those masses to moles</u>, using the <em>elements' respective atomic mass</em>:

  • C ⇒ 73.62 g ÷ 12 g/mol = 6.135 mol C ≅ 6 mol C
  • H ⇒ 8.224 g ÷ 1 g/mol = 8.224 mol H ≅ 8 mol H
  • O ⇒ 98.136 g ÷ 16 g/mol = 6.134 mol O ≅ 6 mol O

So the molecular formula for vitamin C is C₆H₈O₆

8 0
3 years ago
Consider the decomposition of a metal oxide to its elements, where M represents a generic metal. M 3 O 4 ( s ) − ⇀ ↽ − 3 M ( s )
Citrus2011 [14]

Answer:

a) ΔGrxn = 6.7 kJ/mol

b) K = 0.066

c) PO2 = 0.16 atm

Explanation:

a) The reaction is:

M₂O₃ = 2M + 3/2O₂

The expression for Gibbs energy is:

ΔGrxn = ∑Gproducts - ∑Greactants

Where

M₂O₃ = -6.7 kJ/mol

M = 0

O₂ = 0

deltaG_{rxn} =((2*0)+(3/2*0))-(1*(-6.7))=6.7kJ/mol

b) To calculate the constant we have the following expression:

lnK=-\frac{deltaG_{rxn} }{RT}

Where

ΔGrxn = 6.7 kJ/mol = 6700 J/mol

T = 298 K

R = 8.314 J/mol K

lnK=-\frac{6700}{8.314*298} =-2.704\\K=0.066

c) The equilibrium pressure of O₂ over M is:

K=P_{O2} ^{3/2} \\P_{O2}=K^{2/3} =0.066^{2/3} =0.16atm

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