Question

What is the energy of a photon of yellow light with a frequency of 5.2 x 10¹⁴ Hz?​

Answer 1

Answer:

3.4x10⁻¹⁹J is the energy of the photon

Explanation:

To find the energy of a photon from its frequency we must use the equation:

E = hf

Where E is the energy of the photon in J, our incognite

h is Planck's constant = 6.6262x10⁻³⁴Js

And f is the frequency = 5.2x10¹⁴Hz = 5.2x10¹⁴s⁻¹

Replacing:

E = 6.6262x10⁻³⁴Js*5.2x10¹⁴s⁻¹

E = 3.4x10⁻¹⁹J is the energy of the photon