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UkoKoshka [18]
3 years ago
10

Which statement is correct about charges?

Chemistry
2 answers:
V125BC [204]3 years ago
8 0

Answer:

  • A.Opposite charges repel
Sonbull [250]3 years ago
4 0

\:  \:  \:  \:

<h2 /><h2><u>D.Similar charges repel</u></h2>

<u>correct</u><u> me</u><u> if</u><u> I'm</u><u> </u><u>wrong</u>

<h2><u>hope</u><u> it</u><u> helps</u></h2>
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What is the condensing point of water
lorasvet [3.4K]
The condensation point of water is the same as the boiling point of water. This occurs at 212 degrees Fahrenheit or 100 degrees Celcius. As you increase water up to end beyond 100 degrees celcius, the water will boil
7 0
3 years ago
A student submits the following work on the mass number, but he has made a few mistakes. Select the sentences that are incorrect
rewona [7]

Answer

 

Calculating the mass number for an atom requires that we know the atomic number and the number of protons in the atom’s nucleus. The mass number then gives us the average weight of atoms of a given element. However, as long as the number of protons equals the number of neutrons, the values balance out and we always obtain a whole number for the mass number.

Explanation:

those 3

7 0
3 years ago
Given the balanced equation representing a reaction: 2na(s) + cl2(g) → 2nacl(s) + energy if 46 grams of na and 71 grams of cl2 r
igor_vitrenko [27]
Answer is: 2) 117g.
2Na + Cl₂ → 2NaCl
Step 1: calculate amount of substance of sodium and chlorine.
n(Na) = m(Na)÷M(Na) = 46g ÷ 23 g/mol = 2 mol.
n(Cl₂) = m(Cl₂)÷M(Cl₂) = 71g ÷ 71 g/mol = 1 mol.
Step 2: calculate amount of substance and mass of sodium-chloride.
Because both sodium and chlorine react completely, we can use both n to compare with n of NaCl.
n(Na) : n(NaCl) = 2:2, 2 mol : n(NaCl) = 2:2
n(NaCl) = 2mol, m(NaCl) = 2mol ·5805 g/mol = 117 g.

6 0
3 years ago
2. When paleontologists study fossils, which is true of the fossil record that they find?
juin [17]

Answer:

Explanation:

d

7 0
3 years ago
Read 2 more answers
Part V Write the (a) half reaction of oxidation, (b) half reaction of reduction, &amp; (c) the balanced redox reaction for all o
Eduardwww [97]

Answer:

Explanation:

a. Oxidation : 2O + 4e^- ------> 2O^2-

b. Reduction: 2Sr - 4e- -------> Sr^2+

c. Balanced redox reaction

2Sr + O2 ------------> 2Sr O

Oxidation and reduction can be defined by various means, addition of oxygen, removal of hydrogen, removal of electrons. For this reaction, this definition is used, oxidation is the loss of electrons while reduction is the gaining of electrons.

In (a) oxidation half reaction, the valency of oxygen is zero and then moves into lossing two electrons resulting into -2 valency.

In (b) reduction half reaction, the valency of Sr is zero and gains electrons resulting into valency of 2.

In the overall redox reaction, Sr and O2 with valency of 0 each reacts together and form SrO with valency of 2 and -2 respectively, which gives 0 and then balances the equation.

8 0
3 years ago
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