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UkoKoshka [18]
3 years ago
10

Which statement is correct about charges?

Chemistry
2 answers:
V125BC [204]3 years ago
8 0

Answer:

  • A.Opposite charges repel
Sonbull [250]3 years ago
4 0

\:  \:  \:  \:

<h2 /><h2><u>D.Similar charges repel</u></h2>

<u>correct</u><u> me</u><u> if</u><u> I'm</u><u> </u><u>wrong</u>

<h2><u>hope</u><u> it</u><u> helps</u></h2>
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what separation procedure is most likely to happen? .a. freezing a compound will break it down into elements .b. filtering a mix
SOVA2 [1]

Explanation:

i think its B but i'm not fully sure (Correct)

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3 years ago
Given that a for HBrO is 2. 8×10^−9 at 25°C. What is the value of b for BrO− at 25°C?
lara [203]

If Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).

<h3>What is base dissociation constant? </h3>

The base dissociation constant (Kb) is defined as the measurement of the ions which base can dissociate or dissolve in the aqueous solution. The greater the value of base dissociation constant greater will be its basicity an strength.

The dissociation reaction of hydrogen cyanide can be given as

HCN --- (H+) + (CN-)

Given,

The value of Ka for HCN is 2.8× 10^(-9)

The correlation between base dissociation constant and acid dissociation constant is

Kw = Ka × Kb

Kw = 10^(-14)

Substituting values of Ka and Kw,

Kb = 10^(-14) /{2.8×10^(-9) }

= 3.5× 10^(-6)

Thus, we find that if Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).

DISCLAIMER: The above question have mistake. The correct question is given as

Question:

Given that Ka for HBrO is 2. 8×10^−9 at 25°C. What is the value of Kb for BrO− at 25°C?

learn more about base dissociation constant:

brainly.com/question/9234362

#SPJ4

7 0
2 years ago
Explain why chemical equations have to be balanced
vivado [14]
Chemical equations are to be balanced to be able to follow the law of conservation of mass where it says that mass cannot be created or destroyed. Reactions should be that the mass of the reactants is equal to the mass of the products. 
5 0
3 years ago
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If 1.3 L of C3H8 combusts according to the equation below, how much CO2 will be produced?
SCORPION-xisa [38]

Answer:

0.162 moles of CO₂ are produced by this reaction

Explanation:

The reaction is:

C₃H₈(g) + 5O₂(g)  →  3CO₂(g) +4H₂O(g)

As we have the volume of propane, we need to know the mass that has reacted, so we apply density's concept.

Density = Mass / Volume → Density . Volume = Mass

0.00183 g/mL . 1300 mL = Mass → 2.379 g

We determine the moles → 2.379 g . 1mol / 44 g = 0.054 moles

Ratio is 1:3. 1 mol of propane can produce 3 moles of dioxide

Then, 0.054 moles may produce (0.054 .3)/1 = 0.162 moles

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3 years ago
How does experiments help scientist learn about the world
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Experiments test the scientists' ideas.

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