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lesya692 [45]
4 years ago
8

How many grams of LiCl are in 1 L of a 0.05 M LiCl solution

Chemistry
1 answer:
STALIN [3.7K]4 years ago
7 0

Answer:

The answer is 2, 12 g of LiCl in 1 L of solution

Explanation:

We calculate the weight of 1 mol of LiCl:

Weight 1 mol LiCl= Weight Li + Weight Cl =6, 94 g + 35, 45 g= 42,39 g/mol

In a 0.05M solution it means that we have 0.05 moles of compound (in this case, LiCl) in 1 liter of solution:

1 mol---------42, 39 g LiCl

0,05mol-----x=(0,05molx 42, 39 g LiCl)/ 1 mol =2, 1195 g LiCl

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True

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Here is an example: chemical properties include flammability, toxicity, acidity, reactivity. we observe the changes of these properties. Therefore, It's true.

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2 Na + Cl2 → 2 NaCl
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This balanced chemical equation represents a chemical reaction: 6no + 4nh3 → 5n2 + 6h2o what volume of nh3 gas, at standard temp
Liula [17]

The answer is: volume of ammonia gas is 7.4 L.

Chemical reaction: 6NO + 4NH₃ → 5N₂ + 6H₂O.

m(NO) = 15 g; mass of nitrogen(II) oxide.

M(NO) = 30 g/mol; molar mass of nitrogen(II) oxide.

V(NH₃) = ?

n(NO) = 15 g ÷ 30 g/mol.

n(NO) = 0.5 mol; amount of nitrogen(II) oxide.

From chemical reaction: n(NO) : n(NH₃) = 6 : 4.

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V(NH₃) = 0.33 mol · 22.4 L/mol..

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The frequency of red light is less than that of blue light. Which would contain more energy?
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Determine the volume of carbon dioxide gas produced at STP when 2.5 g of nitroglycerin decomposes by this balanced equation. 4C3
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Answer:

0.67 L

Explanation:

Given data:

Volume of carbon dioxide = ?

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Temperature = standard = 273.15 K

Pressure = standard = 1 atm

Solution:

Chemical equation:

4C₃H₅N₃O₉    →    12CO₂ + 10 H₂O + 6N₂ + O₂

Number of moles of nitroglycerine:

Number of moles = mass/ molar mass

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Now we will compare the moles of  nitroglycerine and carbon dioxide from balance chemical equation.

             C₃H₅N₃O₉          :         CO₂

                 4                     :           12

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V = 0.67 L

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