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elena55 [62]
3 years ago
8

A bonfire and a Bunsen burnet form of energy

Chemistry
1 answer:
slavikrds [6]3 years ago
5 0
FORMS OF ENERGY There are nine forms of energy. They are HEAT, LIGHT, SOUND, ELECTRICAL, KINETIC (also called MOVEMENT), ELASTIC, GRAVITATIONAL POTENTIAL, NUCLEAR and CHEMICAL.
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Balancing chemical equations
mojhsa [17]

<span>2H2 + O2 → 2H2O</span>

<span>
</span>

<span>okay???</span>

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4 0
3 years ago
If it requires 18.2 milliliters of 0.45 molar barium hydroxide to neutralize 38.5 milliliters of nitric acid, solve for the mola
Ghella [55]
Hi! :)

Ba(OH)2 + 2 HNO3 → Ba(NO3)2 + 2 H2O

(18.2 mL) x (0.45 M Ba(OH)2) x (2 mol HNO3 / 1 mol Ba(OH)2) / (38.5 mL HNO3) = 0.43 M HNO3
5 0
3 years ago
Read 2 more answers
(6.022*10^23)*2.58=<br> what’s the answer
Sladkaya [172]
The answer would be
1.553676 \times  {10}^{24}
8 0
3 years ago
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Which of the following elements could be transmutated into silver by bombardment with a positron?
Elena L [17]

Answer:

I think it's gold but I'm not sure, sorry

Explanation:

good luck tho :)

6 0
2 years ago
The solubility product constant of pbcl2 is 1.7 × 10−5 . what is the maximum concentration of pb2+ that can be in ocean water th
Sunny_sXe [5.5K]
Answer is: the maximum concentration of Pb²⁺ is 6.8·10⁻³ M.
Chemical reaction 1: PbCl₂(s) → Pb²⁺(aq) + 2Cl⁻(aq).
Chemical reaction 2: NaCl(aq) → Na⁺(aq) + Cl⁻(aq).
Ksp(PbCl₂) = 1.7·10⁻⁵.
c(NaCl) = c(Cl⁻) = 0.0500 M.
Ksp(PbCl₂) = c(Pb²⁺) · c(Cl⁻)².
c(Pb²⁺) = Ksp(PbCl₂) ÷ c(Cl⁻)².
c(Pb²⁺) = 1.7·10⁻⁵ M³ ÷ (0.0500 M)².
c(Pb²⁺) = 0.000017 M³ ÷ 0.0025 M².
c(Pb²⁺) = 0.0068 M = 6.8·10⁻³ M.

3 0
3 years ago
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