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Fudgin [204]
3 years ago
15

Will the sun explode in future?​

Physics
1 answer:
anzhelika [568]3 years ago
6 0

Answer:

Explanation:

The Sun won't explode. ... Eventually (in five or seven billion years time), the Sun's life will come to an end. Our star will swell up, becoming something called a “Red Giant” star. It might even get so big that it swallows the Earth whole.

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Your answer would be : A transmission electron microscope
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Studies of the relationship of the Sun to our galaxy-the Milky Way-have revealed that the Sun is located near the outer edge of
lianna [129]

Mass of the milkyway galaxy :

M_{mw} = \frac{4\pi ^{2}r^{3}}{GT^{2}}\\\\M_{mw} = \frac{4\pi ^{2}(3x10^{4}x9.46x10^{15})^{3}}{6.67x10^{-11}Nm^{2}/Kg^{2}x(7.13x10^{15})^2}\\\\M_{mw } =  2.7x10^{14} Kg

The magnitude of the mass of the Milky Way galaxy = 2.7x10^{14} Kg

<h3>Can galaxies recycle stars?</h3>

Galaxies do not appear to have sufficient matter inside them to keep shaping modern stars at the rates that they do. Presently, astronomers have caught a universe within the act of reusing fabric that it already tossed out, which may clarify the discrepancy. New perceptions give the primary coordinate evidence of gas streaming into distant galaxies that are effectively making infant stars, offering support for the "galactic recycling" theory.

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6 0
2 years ago
Please help with this one
olasank [31]

Answer:

OPTION A is the correct answer

6 0
3 years ago
A car travels in the + x-direction on a straight and level road. For the first 4.00 s of its motion, the average velocity of the
sergejj [24]

Answer:

25 m

Explanation:

The relationship between Velocity, distance and time is given as

S = v/t........................... Equation 1

Where S = average velocity of the car, d = distance covered by the car, t = time

Making d the subject of the equation,

d = vt.................... Equation 2

Given: v = 6.25 m/s, t = 4.00 s.

Substitute into equation 2,

d = 6.25(4)

d = 25 m.

Hence, the distance traveled by the car = 25 m

8 0
4 years ago
A 4.67-g bullet is moving horizontally with a velocity of +357 m/s, where the sign + indicates that it is moving to the right (s
Leni [432]

Answer:

(a)0.531m/s

(b)0.00169

Explanation:

We are given that

Mass of bullet, m=4.67 g=4.67\times 10^{-3} kg

1 kg =1000 g

Speed of bullet, v=357m/s

Mass of block 1,m_1=1177g=1.177kg

Mass of block 2,m_2=1626 g=1.626 kg

Velocity of block 1,v_1=0.681m/s

(a)

Let velocity of the second block  after the bullet imbeds itself=v2

Using conservation of momentum

Initial momentum=Final momentum

mv=m_1v_1+(m+m_2)v_2

4.67\times 10^{-3}\times 357+1.177(0)+1.626(0)=1.177\times 0.681+(4.67\times 10^{-3}+1.626)v_2

1.66719=0.801537+1.63067v_2

1.66719-0.801537=1.63067v_2

0.865653=1.63067v_2

v_2=\frac{0.865653}{1.63067}

v_2=0.531m/s

Hence, the  velocity of the second block after the bullet imbeds itself=0.531m/s

(b)Initial kinetic energy before collision

K_i=\frac{1}{2}mv^2

k_i=\frac{1}{2}(4.67\times 10^{-3}\times (357)^2)

k_i=297.59 J

Final kinetic energy after collision

K_f=\frac{1}{2}m_1v^2_1+\frac{1}{2}(m+m_2)v^2_2

K_f=\frac{1}{2}(1.177)(0.681)^2+\frac{1}{2}(4.67\times 10^{-3}+1.626)(0.531)^2

K_f=0.5028 J

Now, he ratio of the total kinetic energy after the collision to that before the collision

=\frac{k_f}{k_i}=\frac{0.5028}{297.59}

=0.00169

5 0
3 years ago
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