Based on the voltage of the batteries and the internal resistance, the bulb's resistance is 4.595 Ω
<h3>What is the resistance?</h3>
First, find the total emf of the circuit:
= 2 x 1.5V
= 3.0V
The internal resistance is:
= 0.255 + 0.15
= 0.405 Ω
The resistance in the bulb is:
= 3.0 / 0.600 - 0.405
= 4.595 Ω
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Answer:
<em>The total time is: t=451.22 sec</em>
<em>The average speed is: V=34.57 m/s</em>
Explanation:
<u>Average speed</u>
The average speed is calculated by dividing the total distance traveled by an object (x) by the total time it took it to travel that distance (t).

Since the student makes the trip in two parts, we have to calculate the total distance and the total time.
We know the distance to school is 7.8 Km = 7,800 m. The student makes his way home over the same distance, thus the total distance is
x=2*7,800 m=15,600 m
The first trip to school was done at an average speed of v1=32.6 m/s. Knowing the distance and speed, we can calculate the time:

The second trip back home was done at an average speed of v2=36.8 m/s. Let's calculate the second time:

The total time is:


The average speed is:


Answer: wavelength=velocity×period
Explanation:the relation between velocity, wavelength and period is
Wavelength=velocity×period
Answer:
45.8
Explanation:
becuse 9.8+36=45.8 simple
Answer:

Explanation:
In a beta (minus) decay, a neutron in a nucleus turns into a proton, emitting a fast-moving electron (called beta particle) alongside with an antineutrino.
The general equation for a beta decay is:
(1)
where
X is the original nucleus
Y is the daughter nucleus
e is the electron
is the antineutrino
We observe that:
- The mass number (A), which is the sum of protons and neutrons in the nucleus, remains the same in the decay
- The atomic number (Z), which is the number of protons in the nucleus, increases by 1 unit
In this problem, the original nucles that we are considering is iodine-131, which is

where
Z = 53 (atomic number of iodine)
A = 131 (mass number)
Using the rule for the general equation (1), the dauther nucleus must have same mass number (131) and atomic number increased by 1 (54, which corresponds to Xenon, Xe), therefore the equation will be:
