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Tju [1.3M]
2 years ago
6

Two spheres have a gravitational force between

Physics
1 answer:
luda_lava [24]2 years ago
8 0

Answer:

<em>The new force is 2.8125 N</em>

Explanation:

<u>Newton’s Law of Universal Gravitation </u>

Objects attract each other with a force that is proportional to their masses and inversely proportional to the square of the distance.  

\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}

Where:

m1 = mass of object 1

m2 = mass of object 2

r     = distance between the objects' center of masses

G   = gravitational constant: 6.67\cdot 10^{-11}~Nw*m^2/Kg^2

Suppose two spheres have a gravitational force between them of F = 45 N. Now increase the distance to r'=4r. The new force F' is:

\displaystyle F'=G{\frac {m_{1}m_{2}}{(4r)^{2}}}

\displaystyle F'=G{\frac {m_{1}m_{2}}{16r^{2}}}

\displaystyle F'=\frac{1}{16}\ G{\frac {m_{1}m_{2}}{r^{2}}}

Substituting the original value of the force:

\displaystyle F'=\frac{1}{16}\ 45 N

F' = 2.8125 N

The new force is 2.8125 N

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Two airplanes leave an airport at the same time. The velocity of the first airplane is 730 m/h at a heading of 65.3 ◦ . The velo
yanalaym [24]

Answer:

Plane will 741.6959 m apart after 1.7 hour                    

Explanation:

We have given time = 1.7 hr

So if we draw the vectors of a 2d graph we see that the difference in angles is   = 102^{\circ}-65.3^{\circ}=36.7^{\circ}

Speed of first plane  = 730 m/h

So distance traveled by first plane = 730×1.7 = 1241 m

Speed of second plane = 590 m/hr

So distance traveled by second plane = 590×1.7 = 1003 m

We represent these distances as two sides of the triangle, and the distance between the planes as the side opposing the angle 58.6.

Using the law of cosine, r^2 representing the distance between the planes, we see that:

r^2=1241^2+1003^2-2\times 1003\times 1241cos(36.7)=550112.8295

r = 741.6959 m

3 0
3 years ago
A system consists of a disk rotating on a frictionless axle and a piece of clay moving toward it, as shown in the figure above.
cestrela7 [59]

Explanation:

Forgive me If I am wrong, it's been a while since I've studied Torque.

The formula for the angular momentum is

momentum= I*w.

We can also write I*W as 1/2MR^2 * W so the extra mass coming from the block of clay would most likely cause the angular momentum to increase from the amount it was before.

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2 years ago
Earth's rising atmospheric temperature is MOSTLY caused by unnatural
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Greenhouse gases
What is Global Warming? Global warming is the unusually rapid increase in Earth's average surface temperature over the past century primarily due to the greenhouse gases released by people burning fossil fuels.Jun 3, 2010
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2 years ago
A 40.0 -kg box initially at rest is pushed 5.00 m along a rough, horizontal floor with a constant applied horizontal force of 13
salantis [7]

The work done by the applied force = 650 J

Given the mass of the box = 40 kg

The displacement of the box on applying force = 5 m

Applied horizontal force = 130 N

The co-efficient of friction between box and floor is = 0.3

We have to find the work done by the applied force.

Work done by the applied force = Applied Force x Displacement of the box

                                                      = 130 N x 5 m

                                                      = 650 J

[Here the unit Nm is known as Joule(J) ]

We have the co-efficient of friction. So,

The force applied due to friction = Mass of the box x Co-efficient of friction                                                                   x Acceleration due to gravity

                                                      = 40 kg x 0.3 x 9.8

                                                      = 117.6 N

Learn more about Work done at brainly.com/question/62183

#SPJ4

6 0
1 year ago
A particular heat engine has a mechanical power output of 4.00 kW and an efficiency of 26.0%. The engine expels 8.55 103 J of ex
Ivahew [28]

To develop the problem we will start by finding the energy taken by each cycle through the efficiency of the motor and the exhausted energy. Later the work will be found for the conservation of energy in which this is equivalent to the difference between the two calculated energy values. Finally the estimated time will be calculated with the work and the power given,

\text{Efficiency of the heat engine} = \eta = 26\% = 0.26

\text{Energy taken in by the heat engine during each cycle} = Q_h

\text{Energy exhausted by the heat engine in each cycle} = Q_c = 8.55*10^3 J

\eta = 1 - \frac{Q_{c}}{Q_{h}}

0.26 = 1 - \frac{8.55\ast 10^{3}}{Q_{h}}

\frac{8.55* 10^{3}}{Q_{h}} = 0.74

Q_h = \frac{8.55*10^3}{0.74}

Q_h = 11.554*10^3J

PART A)

Work done by the heat engine in each cycle = W

W = Q_h-Q_c

W = 11.554*10^3J-8.55*10^3J

W = 3004J

According to the value given we have that,

P = 4.0kW

P = 4000W

Power is defined as the variation of energy as a function of time therefore,

P = \frac{W}{t}

4000W = \frac{3004J}{t}

t = \frac{3004}{4000}

t = 0.75s

Therefore the interval for each cycle is 0.75s

5 0
3 years ago
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