In our lab experiment on Ohm's law, the power supply is connected to a circuit containing one resistor, and a direct current of
1 answer:
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2000J
Explanation:
Given parameters:
Extension = 0.5m
Spring constant = 16000N/m
Unknown:
Energy stored in the bow string = ?
Solution:
The energy stored in a bow string is an elastic potential energy.
It can be calculated using the expression below;
Elastic energy = K e²
Where k is the spring constant
e is the extension
Input the parameters;
Elastic energy = K e²
= x 16000 x 0.5²
= 2000J
learn more:
Potential energy brainly.com/question/10770261
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