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den301095 [7]
3 years ago
9

Pls help me answer this question I'll make you Brainliest​

Biology
1 answer:
aalyn [17]3 years ago
4 0
So the dark butterfly camouflages better on the tree. Where as the white one can clearly be seen and identified. A predator will also easily spot it and kill it. The dark butterfly has evolved over time to the color that it is, to best help it survive. This is also shown in the tread on the graph.


Hope this helps!!
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The following flow of energy occurs in the trophic levels in an ecosystem:
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The answer is <span>b. wolf.
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Organisms from the higher trophic levels consume organisms from the lower trophic level. In this process, energy is lost as metabolic heat. Thus, primary producers, such as sedge, contain the greatest amount of energy originally from the sunlight. The next trophic level belongs to primary consumers, such as arctic hare, that consume primary producers resulting in less energy. Similarly, arctic fox eats arctic hare, and energy is lost again. The highest trophic level is tertiary consumers such as wolf, therefore, the wolf contains the least amount of energy.
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3 years ago
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En un cruce entre peces naranjas y peces grises se obtiene una generación (f1) de 50% peces grises . Realice el cruce y explique
Ilya [14]

Answer:

Uno de los progenitores es heterocigoto para color naranja (Nn) y el otro parental es homocigoto recesivo para gris (nn). Al haber una cruza entre un homocigoto recesivo y un heterocigoto, la 50% de la progenie expresa color naranja (Nn), mientras que el otro 50% expresa color gris (nn).

Explanation:

<u>Datos disponibles:</u>

  • Cruce entre peces naranjas y peces grises
  • 50% de la F1 son peces grises
  • Naranja dominante sobre gris

Podemos nombrar el alelo dominante para color naranja <em>N</em>, y al alelo recesivo  para color gris <em>n</em>.

Para que en un cruce entre dos fenotipos distintos, el 50% de la primer camada exprese uno de estos fenotipos, entonces uno de los parentales debe ser heterocigoto, mientras que el otro parental debe ser homocigoto recesivo. De esta forma 50% de la primera generación expresara uno de los fenotipos, mientras que el otro 50% expresará el otro fenotipo.

Supongamos que uno de los parentales lleva el genotipo <em>Nn</em>, y el otro parental es <em>nn</em>.

Cruce:

Parental)      Nn    x     nn

Gametas)   N    n       n    n

Fenotipos) Naranja     Gris

Cuadro de Punnett)      N           n

                            n       Nn         nn

                            n       Nn         nn

F1)  2/4 = 1/2 = 50% de la progenie tendrá genotipo heterocigoto, Nn

     2/4 = 1/2 = 50% de la progenie tendrá genotipo homocigota recesivo,    

     nn

     50% de la progenie será color naranja (Nn)

     50% de la progenie será color gris (nn)

               

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I have a feeling that it’s 5
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Compare passive and active transport through the cell membrane, including energy use and concentration gradients.
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