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vazorg [7]
3 years ago
8

A trolley at rest is pushed to accelerate at a

Physics
1 answer:
laila [671]3 years ago
6 0
V^2 = 2a S
V = square root ( 2 x 0.5 . 4)
V = 2 m/s
Answer is B
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Please help i will mark brainliest
valkas [14]
Im pretty sure the answer is c; velocity is usually measure by a vector :)
6 0
3 years ago
Read 2 more answers
Diffinition of nebula
GrogVix [38]

nebulae, nebulæ, or nebulas) is an interstellar cloud of dust, hydrogen, helium and other ionized gases. Originally, nebula was a name for any diffuse astronomical object, including galaxies beyond the Milky Way. The Andromeda Galaxy, for instance, was once referred to as the Andromeda Nebula (and spiral galaxies in general as "spiral nebulae") before the true nature of galaxies was confirmed in the early 20th century by Vesto Slipher, Edwin Hubble and others.

Most nebulae are of vast size, even hundreds of light years in diameter.[3] Although denser than the space surrounding them, most nebulae are far less dense than any vacuum created on Earth – a nebular cloud the size of the Earth would have a total mass of only a few kilograms. Many nebulae are visible due to their fluorescence caused by the embedded hot stars, while others are so diffuse they can only be detected with long exposures and special filters. Some nebulae, are variably illuminated by T Tauri variable stars. Nebulae are often star-forming regions, such as in the "Pillars of Creation" in the Eagle Nebula. In these regions the formations of gas, dust, and other materials "clump" together to form denser regions, which attract further matter, and eventually will become dense enough to form stars. The remaining material is then believed to form planets and other planetary system objects.

The range of objects called nebula are very diverse, have diverse origins, and final ends.

Contents <span> [hide] </span><span><span>1Observational history</span><span>2Formation</span><span><span>3Types of nebulae</span><span><span>3.1Classical types</span><span>3.2Diffuse nebulae</span><span><span>3.3Planetary nebulae</span><span>3.3.1Protoplanetary nebula</span></span><span>3.4Supernova remnants</span></span></span><span><span>4Notable named nebulae</span><span>4.1Nebula catalogs</span></span><span>5See also</span><span>6References</span><span>7<span>External links

</span></span></span>

7 0
4 years ago
The amount of straight pipe needed to bend a given radius. Also, the actual length of the conduit that will be bent.
slava [35]

Development length: The actual length of the bent conduit. Gain: Since a conduit bends radially rather than at an angle, the total length will not match the length required for all bends. Gain is the amount of space that is saved by a 90^{0} curve.

<h3>Bent Conduit</h3>

Conduit benders from Klein Tools are built to function and last longer than even the highest professional standards. To ensure a favourable experience and significantly enhance the final result of your project, it is advised that you become familiar with bending concepts, procedures, and the bender's capabilities. The benders are labelled with various alignment symbols to enable the operator make the bends required to complete any job. This aids bending while executing a ground or air bend. Arrow, teardrop, star point, and angle markings are the symbols on the Klein Tools benders. On certain bender head sides, you can see these markings.

Learn more about bent conduit here:

brainly.com/question/5023977

#SPJ4

8 0
2 years ago
A variação no comprimento de uma barra de alumínio foi de 0,0002m. Calcular a variação na temperatura a =22x10-⁶
Furkat [3]

Answer:

1.82°C

Explanation:

presumir inicial comprimento = l₀ = 5 m

dado que:

coeficiente de expansão (α) = 22 x 10⁻⁶, A variação no comprimento (ΔL) = 0.0002 m,

inicial comprimento = l₀ = 5 m

variação na temperatura = ΔT

para Calcular a variação na temperatura,  nós usamos a fórmula:

\Delta L=l_0\alpha \Delta T

substituindo valores:

0.0002=5*22*10^{-6}\Delta T\\\Delta T=\frac{0.0002}{5*22*10^{-6}}\\ 5*22*10^{-6}=1.82^0C

variação na temperatura = 1.82°C

8 0
3 years ago
A lunar exploration vehicle was created by a research team. It weighs 3,000 kg on the earth. It needs an acceleration of 10 m/s2
Arada [10]
Answer = 30,000 N

EXPLANATION

Applying Newton’s second of law of motion, which in summary, states that t<span>he acceleration of an object... is directly proportional to the magnitude of the net force... and inversely proportional to the mass of the object.
</span><span>
Therefore, Force = Mass * Acceleration
F = ma

Mass, m = </span><span>3,000 kg
</span>Acceleration, a = <span>10 m/s</span>²<span>
</span>Force, F = 3,000 × 10
= 30,000 N
6 0
3 years ago
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