The first one is BC
The second one is AB
5/8 - 3/10
Find the common denominator:
Multiples of 8: 8, 16, 24, 32, 40 (8 x 5 = 40)
Multiples of 10: 10, 20, 30, 40 (10 x 4 = 40)
5/8 = 5*5 / 8*5 = 25/40
3/10 = 3*4 / 10 *4 = 12/40
Now you have 25/40 - 12/40
25 -12 = 13
Answer = 13/40
The answer is A.
D = rt. The first car's rate is r, and the other one, going faster, is r + 12. The time they travel is 2 hours. Since one is going faster than the other, he has gotten farther. But, regardless of that, the distance between them is 232. So the distance the first one travels, r*t, which 2r, plus the distance the second one travels, 2(r+12) = 232. 2r + 2r + 24 = 232. Solve for r. 4r = 208 and r = 52. The slower one goes 52 and the faster one goes 64
Answer: 3^2 * 3^8
Step-by-step explanation: 3^(4-2) * 3^(5+3)
Every even number is 2 away from the last.
0, 2, 4, 6, 8, 10, 12, 14...etc.
If we had an even number p, then the next three even numbers would be
p+2, p+4, and p+6.
<em>(If we had an odd number p, then the next three even numbers would be</em>
<em>p+1, p+3, and p+5. I'm not sure if p is even is implied in the question. Technically the answer would be p - p mod 2 + 2, where p is an interger...that gets into more technical function stuff, though.)</em>
