According to the following formula, the answer is 2,300 g or 2.3 kg:
Volume (m)/Mass (m) Equals Density (p) (V)
Here, the density is 1.15 g/mL, allowing the formula described above to result in a mass of 2.00 L:
p=m/V
1.15 g/mL is equal to x g/2.00 L or x g/2,000 mL.
2,000 mL of x g = 1.15 g of g/mL
2.3 kg or 2,300 g for x g.
<h3>How many grams of glucose are in a 1000ml bag of glucose 5?</h3>
Its active ingredient is glucose. This medication includes 50 g of glucose per 1000 ml (equivalent to 55 g glucose monohydrate). 50 mg of glucose is present in 1 ml (equivalent to 55 mg glucose monohydrate). A transparent, nearly colourless solution of glucose in water is what is used in glucose intravenous infusion (BP) at 5% weight-to-volume.
Patients who are dehydrated or who have low blood sugar levels get glucose intravenously. Other medications may be diluted with glucose intravenous infusion before being injected into the body. Other diseases and disorders not covered above may also be treated with it.
learn more about glucose intravenous infusion refer
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Answer:
The color orange is named after the fruit
The answer is B.
Temperature is just another term for the average kinetic energy of a substance.
Answer:
Final angular velocity is 35rpm
Explanation:
Angular velocity is given by the equation:
I1w1i + I2w2i = I1w1f -I2w2f
But the two disks are identical, so Ii =I2
wf can be calculated using
wf = w1i - w2i/2
Given: w1i =50rpm w2i= 30rpm
wf= (50 + 20) / 2
wf= 70/2 = 35rpm
Answer:
The velocity of the other fragment immediately following the explosion is v .
Explanation:
Given :
Mass of original shell , m .
Velocity of shell , + v .
Now , the particle explodes into two half parts , i.e 
.
Since , no eternal force is applied in the particle .
Therefore , its momentum will be conserved .
So , Final momentum = Initial momentum
The velocity of the other fragment immediately following the explosion is v .
