<span>Let's convert the speed to m/s:
speed = (55 mph) (1609.3 m / mile) (1 hour / 3600 seconds)
speed = 24.59 m/s
Let's convert the mass to kilograms:
mass = (2135 lb) (0.45359 kg / lb)
mass = 968.4 kg
We can find the kinetic energy KE:
KE = (1/2) m v^2
KE = (1/2) (968.4 kg) (24.59 m/s)^2
KE = 292780 joules
The kinetic energy of the automobile is 292780 joules.</span>
Displacement = (straight-line distance between the start point and end point) .
Since the road east is perpendicular to the road north,
the car drove two legs of a right triangle, and the magnitude
of its final displacement is the hypotenuse of the triangle.
Length of the hypotenuse = √ (215² + 45²)
= √ (46,225 + 2,025)
= √ 48,250
= 219.7 miles .
Answer:
Speed of the glacier, 
Explanation:
Given that,
The average speed of Hubbard Glacier, 
We need to find speed of advance of the glacier in m/s. As we know that,
1 meter = 3.28 feet
And
Using the above conversions, we can write the value of average speed is :
So, the speed of advance of the glacier is 
. Hence, this is the required solution.
Answer:
m' = 20.1024 kg
Explanation:
Given that for standard object
m = 7.98 kg
a= 2.5244 m/s²
From Second law of Newtons
F= m a
Now by putting the values
F = 2.5244 x 7.98 N
F= 20.144 N
In second object
F'= m ' a'
F' = F ( given that)
20.144 = 1.0021 m'
m' = 20.1024 kg
Earth's magnetic field<span>, also known as the </span>geomagnetic field<span>, is the </span>magnetic field<span> that extends from the </span>Earth's interior<span> out into space, where it meets the </span>solar wind<span>, a stream of </span>charged particles<span> emanating from the </span>Sun. Its magnitude at the Earth's surface ranges from 25 to 65 microteslas<span> (0.25 to 0.65 </span>gauss<span>).</span>
