When is a body said to be motion (movement )?

When going from a fast speed to a slow speed how is light bent?

Zolol [24]

Toward the normal line

4 0

3 years ago

A beam of unpolarized light with a power of 1.0 mW passes through two ideal linear polarizers in series. An ideal polarizerabsor

Mashutka [201]

Answer:

the axes of the two polarizers are aligned, the angle between this axis must be zero

Explanation:

Polarizers are anisotropic systems where absorption is selective in each axis, in this case they indicate that on an axis they let 100% pass and perpendicular to this axis no light passes.

The first polarizer defines a direction of light that of its axis, it is said that the light is polarized, when this light reaches the second polarized, so that it can pass the axis must be in the direction of the polarized beam.

In summary, the axes of the two polarizers are aligned, the angle between this axis must be zero

3 0

3 years ago

In nuclear reaction 5 kg of reactants give 2kg of products

dlinn [17]

Choice A is correct.======Kinetic energy equation: KE = (1/2)(m)(v²)This tells us that KE is directly proportional to mass and the square of velocity. In other words, the more mass and more velocity an object has, the more kinetic energy.If an object is sitting at the top of a ramp, there is no velocity and therefore no kinetic energy. Choices B and D are wrong.A golf ball has more mass than a ping-pong ball, so a ping-pong ball would have less kinetic energy than a golf ball rolling off the end of a ramp. Choice C is wrong.Choice A is correct.

6 0

3 years ago

Three forces act on a moving object. One force has a magnitude of 83.7 N and is directed due north. Another has a magnitude of 5

LekaFEV [45]

Answer:

$|\vec{F}_3| = 102.92 \ N$

$\theta = 57 \° 24 ' 48''$

Explanation:

For an object to move with constant velocity, the acceleration of the object must be zero:

$\vec{a} = \vec{0}$ .

As the net force equals acceleration multiplied by mass , this must mean:

$\vec{F}_{net} = m \vec{a} = m * \vec{0} = \vec{0}$ .

So, the sum of the three forces must be zero:

$\vec{F}_1 + \vec{F}_2 + \vec{F}_3 = \vec{0}$ ,

this implies:

$\vec{F}_3 = - \vec{F}_1 - \vec{F}_2$ .

To obtain this sum, its easier to work in Cartesian representation.

First we need to define an Frame of reference. Lets put the x axis unit vector $\hat{i}$ pointing east, with the y axis unit vector $\hat{j}$ pointing south, so the positive angle is south of east. For this, we got for the first force: