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tatyana61 [14]
2 years ago
12

005 10.0 points

Physics
1 answer:
velikii [3]2 years ago
8 0

Answer:

16.6 N

Explanation:

m = 0.52 kg, v₀ = 0, v = 8.6 m/s, t = 0.27 s

a = (v - v₀)/t

F = ma = m(v - v₀)/t = 0.52 (8.6 - 0)/0.27 = 16.6 N

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A student wished to add a new experiment to Chapter 2 by investigating whether the mass of water changes when it is heated. The
Valentin [98]

Answer:

mass conservation is valid for all closed system where the mass will remain in the system always

Explanation:

Conservation of mass is applicable everywhere in classical physics

Here we can also apply mass conservation as we know that the initially the beaker and its water content is having total mass of 109.44 g

m_1 = 109.44 g

now when we heated it to higher temperature then its total mass will be lesser than the initial mass this is because some of the water may evaporate from the system.

Here if we repeat the same experiment with closed boundary then we can see that total mass will be conserved

So here mass conservation is valid for all closed system where the mass will remain in the system always

7 0
4 years ago
When the compasses are moved close to a wire with a current which will the compasses point
Sindrei [870]
<span>In this demonstration, there is a single compass and a piece of wire that is perpendicular to the plane that the compass sits on. The wire with current flowing through it can alter the direction the compass needle points.</span>
4 0
3 years ago
Read 2 more answers
A woman fires a rifle with barrel length of 0.5400 m. Let (0, 0) be where the 125 g bullet begins to move, and the bullet travel
dybincka [34]

Answer:

Explanation:

Given that,

Length of barrel =0.54m

Mass of bullet=125g=0.125kg

Force extend

F=16,000+10,000x-26,000x²

a. Work done is given as

W= ∫Fdx

W= ∫(16,000+10,000x-26,000x² dx from x=0 to x=0.54m

W=16,000x+10,000x²/2 -26,000x³/3 from x=0 to x=0.54m

W=16,000x+5,000x²- 8666.667x³ from x=0 to x=0.54m

W= 16,000(0.54) + 5000(0.54²) - 8666.667(0.54³) +0+0-0

W=8640+1458-1364.69

W=8733.31J

The workdone by the gas on the bullet is 8733.31J

b. Work done is given as

Work done when the length=1.05m

W= ∫Fdx

W= ∫(16,000+10,000x-26,000x² dx from x=0 to x=1.05m

W=16,000x+10,000x²/2 -26,000x³/3 from x=0 to x=1.05m

W=16,000x+5,000x²- 8666.667x³ from x=0 to x=1.05mm

W= 16,000(1.05) + 5000(1.05²) - 8666.667(1.05³) +0+0-0

W=16800+5512.5-10032.75

W=12,279.75J

The workdone by the gas on the bullet is 12,279.75J

3 0
3 years ago
All electric circuits have devices that are run by _____ energy.
KATRIN_1 [288]

Answer: electrical energy

Explanation:

Electrical energy

8 0
3 years ago
You are holding the axle of a bicycle wheel with radius
erastova [34]

Answer:

The angular acceleration of the wheel is -6.54 rad/s²

Explanation:

We'll use the equations of motion for this.

w = 2πf

f = 75 rpm = 1.25 rps = 1.25 rev/s

w₀ = initial angular velocity = 2π × 1.25 = 7.85 rad/s

w = final angular velocity = 0 rad/s

t = 1.2 s

α = ?

w = w₀ + αt

0 = 7.85 + 1.2α

α = 7.85/1.2 = - 6.54 rad/s²

6 0
4 years ago
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