Answer:
Part 1) 
Part 2) 
Part 3) 
Step-by-step explanation:
<u><em>The complete question is</em></u>
Consider this right triangle. 21 29 20 Write the ratio equivalent to: Sin B - CscA- Cot B
The picture of the question in the attached figure
Part 1) Write the ratio equivalent to: Sin B
we know that
In the right triangle ABC
----> by SOH (opposite side divided by the hypotenuse)
substitute the values

Part 2) Write the ratio equivalent to: Csc A
we know that
In the right triangle ABC

-----> by SOH (opposite side divided by the hypotenuse)
substitute the values

therefore

Part 3) Write the ratio equivalent to: Cot A
we know that
In the right triangle ABC

-----> by TOA (opposite side divided by the adjacent side)
substitute the values

therefore

Answer:
id like to help but the picture is really blurry so im afraid that i cant. but i know there are others who can!
Step-by-step explanation:
i hope this helps you!
Answer:
112
Step-by-step explanation:
To find the least common multiple, we break the numbers down into prime factors
7 = 7
14 = 7*2
16 = 2*8 = 2*4*2 = 2*2*2*2
Then we take the largest number of times it appears in all the numbers
2 appears 4 times so we take take four 2's
7 appears 1 so we take one 7
LCM = 2*2*2*2*7
LCM = 112
Answer:
The answer to your question is:
Step-by-step explanation:
1.-






2sec
2.-
sec²x - tanxsecx





