Question

Triangle ABC is dilated using the dilation rule D0.5(x, y) to form triangle A'B'C'. Point A is located at (10, 7.5), point B is located at (–5, 2), and point C is located at (0.5, –7).

Answer 1

Answer:

The coordinates of A' are $A'(x,y) = (5, 3.75)$.

The coordinates of B' are $B'(x,y) = (-2.5, 1)$.

The coordinates of C' are $C'(x,y) = (0.25, -3.5)$.

Step-by-step explanation:

The statement is incomplete, we present the complete statement below: Triangle ABC is dilated using the dilation rule $D = 0.5\cdot (x,y)$ to form triangle A’B’C’. Point A is located at $A(x,y) = (10, 7.5)$, point B is located at $B(x,y) =(-5,2)$, and point C is located at $C(x,y) =(0.5,-7)$. What are the coordinates of A’? What are the coordinates of B’? What are the coordinates of C’?

We proceed to calcultate the coordinates of the triangle A'B'C' hereafter:

What are the coordinates of A'?

$A'(x,y) = 0.5\cdot A(x,y)$ (1)

$A'(x,y) = 0.5\cdot (10, 7.5)$

$A'(x,y) = (5, 3.75)$

The coordinates of A' are $A'(x,y) = (5, 3.75)$.

What are the coordinates of B'?

$B'(x,y) = 0.5\cdot B(x,y)$ (2)

$B'(x,y) = 0.5\cdot (-5,2)$

$B'(x,y) = (-2.5, 1)$

The coordinates of B' are $B'(x,y) = (-2.5, 1)$.

What are the coordinates of C'?

$C'(x,y) = 0.5\cdot C(x,y)$ (3)

$C'(x,y) = 0.5\cdot (0.5,-7)$

$C'(x,y) = (0.25, -3.5)$

The coordinates of C' are $C'(x,y) = (0.25, -3.5)$.

Answer 2

Answer:

(5, 3.75)

(-2.5, 1)

(0.25, -3.5)