50√•15 I need help pls

Sergio039 [100]

3/4. Keep change flip. 1/2 x 3/2 = 3/4

5 0

3 years ago

Suppose that the dollar cost of producing x radios is c(x) = 400 + 20x - 0.2x 2. Find the marginal cost when 30 radios are produ

My name is Ann [436]

C(x) = 400 + 20x - 0.2x²

c(30) = 400 + 20(30) - 0.2(30)²

= 400 + 600 - 0.2(900)
= 1000 - 180
= 820

It costs $820 when 30 radios are produced.

Marginal cost is how much it would cost to make one MORE of the same product so now we find how much it costs to produce 31 radios and compare the two.

c(31) = 400 + 20(31) - 0.2(31)²

= 400 + 620 - 0.2(961)
= 1020 - 192.2
= 827.8 or ≈828.

Now we find the difference which means we subtract the two.

828 - 820 = 8.

Your marginal cost is $8.

To compare we can also do 29 radios.

c(29) = 400 + 20(29) - 0.2(29)² = 811.8 or ≈812

820 - 812 = 8.

7 0

3 years ago

What is 2/3x + 1/4x= 6 ??????

erik [133]

Use Cymath to find your answer

8 0

2 years ago

Read 2 more answers

The number of windows on each floor form an arithmetic sequence; 124 windows on the first floor, 116 windows on the second floor

zubka84 [21]

Answer:

Formula is 132 - 8n, and there are 52 windows on 10th floor.

Step-by-step explanation:

difference = 116-124 = -8 ( 8 less windows for every floor you go up)

the first fllor has 124 windows

Formula:

$a_{1} = 124$

$a_{n} = 124 + (-8)(n - 1)$ = 132 - 8n

10th Floor:

$a_{10} = 124 + (-8)(10 - 1) = 124 + (-8)(9) = 124 - 72 = 52 windows$

6 0

2 years ago

The distribution of resistance for resistors of a certain type is known to be normal, with 10% of all resistors having a resista

baherus [9]

Answer:

The mean is 9.65 ohms and the standard deviation is 0.2742 ohms.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

10% of all resistors having a resistance exceeding 10.634 ohms

This means that when X = 10.634, Z has a pvalue of 1-0.1 = 0.9. So when X = 10.634, Z = 1.28.

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{10.634 - \mu}{\sigma}$