An ionic compound is composed of ionic bonds that are formed by transfer of electrons from one atom to the other. The atom that loses electrons acquires a positive charge (cation) while that which gains electrons acquires a negative charge.
In the case of sodium chloride; Sodium Na has 1 electron in its outer orbital while Chlorine Cl has 7 electrons. Thus, Cl requires 1 electron to complete its octet. This electron is donated by Na.
Thus, NaCl is essentially, Na⁺Cl⁻
Ans D) Chlorine becomes an anion by gaining an electron from sodium
The answer is
e o i and a
not really sure forgive me if im wrong
3NO₂ + H₂O→2HNO₃ + NO
n(NO)=n(NO₂)/3
n(NO)=0.83/3=0.277 mol
Answer:
Therefore we can say that the total number of electrons present in $ p - $ orbital of chlorine atoms is eleven.
Explanation:
