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son4ous [18]
3 years ago
8

Consider the following system at equilibrium at 723 K: 2 NH3 (g) 26.6 kcal N2 (g) 3 H2 (g) Indicate whether each individual chan

ge would favor the production of N2 (g). Evaluate each change separately, assuming that all other conditions remain constant.
Chemistry
1 answer:
ZanzabumX [31]3 years ago
4 0

Answer:

- To increase the temperature as it is a reactant in terms of its endothermicity.

- To remove it will enable more space for the reactant to favor its production.

- To add more reactant in order to increase its equilibrium concentration.

Explanation:

Hello,

The undergoing chemical reaction is:

2NH_3(g)\rightleftharpoons 3H_2(g)+N_2(g)

Thus, in order to intensify the amount of nitrogen as the chemical reaction is endothermic, considering the Le Chatelier's principle we state:

- To increase the temperature as it is a reactant in terms of its endothermicity.

- To remove it will enable more space for the reactant to favor its production.

- To add more reactant in order to increase its equilibrium concentration.

Best regards.

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1. Calculate the RFM of Fe(NO3)2
miss Akunina [59]

Answer:

The Relative Formula Mass of Fe(NO₃)₂ is 179.8524 grams

Explanation:

The Relative Formula Mass is the mass of one mole of a compound expressed in grams, obtained by adding together the Relative Atomic Masses, RAM, of the elements which makes the compound

The Relative Formula Mass of a compound is the same as its Relative Molecular Mass

The relative formula mass of Fe(NO₃)₂ is given as follows;

The relative atomic mass of Fe = 55.845 amu

The relative atomic mass of nitrogen, N = 14.0067 amu

The relative atomic mass of oxygen, O = 15.999 amu

Therefore, we have;

The formula mass of Fe(NO₃)₂ = (55.845 + 2×(14.0067 + 3×15.999)) amu = 179.8524 amu

The Relative Formula Mass of Fe(NO₃)₂ = 179.8524 grams.

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The group is might be labeled as VIIB or VIIA.
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Answer:

MgCl2 > C4H9OH > CH4 > C3H8.

Explanation:

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MgCl2 is soluble in water. Water essentially breaks down the ionic crystal lattice and the resulting solution is slightly basic.

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