Let n = required random sample size.
Assume that the population standard deviation is known as σ.
Let m = sample mean.
At the 95% confidence level, the expected range is
(m - k(σ/√n), m + k(σ/√n))
where k = 1.96.
Therefore the error margin is 1.96(σ/√n).
Because the error margin is specified as 3% or 0.03, therefore
(1.96σ)/√n = 0.03
√n = (1.96σ)/0.03
n = 128.05σ²
This means that the sample size is about 128 times the population variance.
Answer:
Smallest sample size = 128.05σ², where σ = population standard deviation.
Answer:
12 is mean 11 is median range is 14
Step-by-step explanation:
For the Mean
Add all the numbers up
16 + 9 + 20 + 10 =55
12 + 6 + 8 + 15 = 41
55 + 41 = 96
There are 8 numbers so we divide by 8
96/8 = 12
Range is Smallest number minus biggest so 20 - 6 = 14
Answer:
Statistics as numerical facts involves the use of numbers from a sample in determining the mean, media, mode, variance etc of the given sample of numbers. It is useful in giving more information about an Economic state.
Statistics as a discipline or field of study is the art of the usage of these data in the interpretation and analysis of the different data available.
Distribute the 2 on the left to get 2e + 8 = 8e - 20
Add 20 to both sides and subtract 2e from both sides.
28 = 6e
Divide both sides by 6.
e = 14/3
Answer:
B
Step-by-step explanation:
Solve the first half of the equation-
-8x+3 >/=27
-3 -3
-8x>/=24
divided by -8 on both sides
x</=-3
Now for the second side:
-13x+5>/= 57
-5 -5
-13x>/=52
divide by -13 in both sides
x</=-4
We now have two equations. The answer would be x</=-3 because -4 is also less than three, so it can be simplified down to -3. I know you might not have needed the explanation since it’s just khan academy, but I figured I’d explain it anyway :)
