Answer:
n=3
Step-by-step explanation:
20+20+20 length +width+ height
20×3
We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.
We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.
Formula for combination:

Where
represents the number of objects/people in the set and
represents the number of objects/people being chosen from the set
There are 23 people in the set and 10 people being chosen from the set


Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get

Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!
~ Padoru
What city lol? sorry i just need to answer so i can ask question bc i’m lost lol
2x - y = 0
2x = y
3x - 2(2x) = -3
3x - 4x = -3
-x = -3
x = 3
2(3) = y
6 = y