Is there suppose to be a picture attached?
(2x^2+6x-11)-(5x^2-x+7)
Pretend that there is a -1 in front of the second bracket
-1(5x^2-x+7)=-5x^2+x-7
2x^2+6x-11-5x^2+x-7
2x^2-5x^2+6x+x-11-7 ( combine like terms)\
-3x^2+7x-18
Answer: d. -3x^2+7x-18
(26 x 1334) + (19 x 749)
This would equal 34684 + 14231 or 48915
$48915 is how much it costs.
Hope this helps :)
The answer is: "
40 % " .
_______________________________________________Note:_______________________________________________ If "3/5" of the students ride the bus, then "2/5" do not ride the bus".
Since: "3/5" + "2/5" = "(3 + 2)" / 5 = 5/5 = "1" (as in "1 whole").
1 – (3/5) = (5/5) – (3/5) = (5 – 3) / 5 = 2/5.
________________________________________________Now, express: "2/5" as a percentage ;
→ "2/5" = "x / 100 " ; Solve for "x"
Cross-multiply: Note:
→ Given: "
" = "
" ;
→ " bc = ad" ; {" b
0 ; d
0 "} .
_______________________________________________________As such:
→ "
" = "
" ;
→ " 5x = (2)*(100) " ;
→ Solve for "x" ;
→ " 5x = 200 " ;
→ Divide each side of the equation by "5" ;
to isolate "x" on one side of the equation; & to solve for "x" ;
→ " 5x / 5
= 200 / 5 " ;
to get:
→ "
x = 40 " ;
_________________________________________So; we have:
→ "2/5" = "
40 / 100 " ;
→ "2/5" = "
40 % " .
____________________________________________The answer is: "
40 % " .
____________________________________________